找出哪个按钮是按下的，而长按压和抽头不同。斯威夫特

Question

所以我有一个长而短的按钮的听众，但我需要知道什么按钮被按下。是否有可能找出哪个按钮按下了龙头和长功能，或者我需要为每个按钮做两个功能？

let tapGesture = UITapGestureRecognizer(target: self, action: #selector(tap))
let longGesture = UILongPressGestureRecognizer(target: self, action: #selector(long))
longGesture.minimumPressDuration = 0.5
smallOption.addGestureRecognizer(tapGesture)
mediumOption.addGestureRecognizer(tapGesture)
largeOption.addGestureRecognizer(tapGesture)
smallOption.addGestureRecognizer(longGesture)
mediumOption.addGestureRecognizer(longGesture)
largeOption.addGestureRecognizer(longGesture)

@objc func tap(_ sender: UIGestureRecognizer){
    print("short-press")
}
@objc func long(_ sender: UIGestureRecognizer){
    print("long-press")
}

Answer 1

主要问题是，在这种情况下，这两个手势将只添加到largeOption按钮！为了澄清，只为一个组件添加了手势，在您的示例中，应该只为最新的组件(即largeOption)添加该手势：

smallOption.addGestureRecognizer(tapGesture) <-- skipped
mediumOption.addGestureRecognizer(tapGesture) <-- skipped
largeOption.addGestureRecognizer(tapGesture) <-- added
smallOption.addGestureRecognizer(longGesture) <-- skipped
mediumOption.addGestureRecognizer(longGesture) <-- skipped
largeOption.addGestureRecognizer(longGesture) <-- added

从逻辑上讲，这可能是你问题的答案：

是否有可能找出哪个按钮按下了龙头和长函数，或者我需要为每个按钮执行两个函数？

您需要为每个按钮添加两个手势，因为特定的手势只能添加到一个视图中。

但是，除了@objc func tap(_ sender: UIGestureRecognizer)和@objc func long(_ sender: UIGestureRecognizer)现有的操作方法之外，您不必声明新的操作方法。您可以做的是检查sender的视图。例如：

假设我们为每个按钮手动添加了两个手势：

// gestures:
let smallOptionTapGesture = UITapGestureRecognizer(target: self, action: #selector(tap))
let smallOptionLongGesture = UILongPressGestureRecognizer(target: self, action: #selector(long))
smallOptionLongGesture.minimumPressDuration = 0.5

let mediumOptionTapGesture = UITapGestureRecognizer(target: self, action: #selector(tap))
let mediumOptionLongGesture = UILongPressGestureRecognizer(target: self, action: #selector(long))
mediumOptionLongGesture.minimumPressDuration = 0.5

let largeOptionTapGesture = UITapGestureRecognizer(target: self, action: #selector(tap))
let largeOptionLongGesture = UILongPressGestureRecognizer(target: self, action: #selector(long))
largeOptionLongGesture.minimumPressDuration = 0.5

// adding them:
smallOption.addGestureRecognizer(smallOptionTapGesture)
mediumOption.addGestureRecognizer(mediumOptionTapGesture)
largeOption.addGestureRecognizer(largeOptionTapGesture)

smallOption.addGestureRecognizer(smallOptionLongGesture)
mediumOption.addGestureRecognizer(mediumOptionLongGesture)
largeOption.addGestureRecognizer(largeOptionLongGesture)

因此，你可以做的是：

@objc func tap(_ sender: UIGestureRecognizer) {
    // an example of how you could check the button
    if sender.view == smallOption {
        print("small short-press")
    } else if sender.view == mediumOption {
        print("medium short-press")
    } else if sender.view == largeOption {
        print("large short-press")
    }
}
@objc func long(_ sender: UIGestureRecognizer) {
    // you could apply the same above approach here
}

另一个选项是分别为每个按钮创建操作方法。

Answer 2

对于每个按钮，您不需要为相同的手势提供两个函数。将方法定义更改为接受UIButton (在您的情况下)，而不是UIGestureRecognizer。然后，通过直接验证标签或类型来检查发送者.

@objc func tap(_ sender: UIButton){
  switch sender {
  case button1: // or by tags of buttons
  case button2:
  ...
  default: break
}