基于递增键的Javascript对象合并数组

Question

这就是我所拥有的:我希望合并以"path-"+i开头的对象。最后从键中去掉“路-i”。

  var arr = [
  {
    "key": "path-0-mp4",
    "value": [
      "media/video/01.mp4",
      "media/video/01_hd.mp4"
    ]
  },
  {
    "key": "path-0-quality",
    "value": [
      "720p",
      "1080p"
    ]
  },
  {
    "key": "path-1-mp4",
    "value": [
      "media/video/02.mp4",
      "media/video/02_hd.mp4"
    ]
  },
  {
    "key": "path-1-quality",
    "value": [
      "SD",
      "HD"
    ]
  }

]

这是一个理想的结果：

 var arr = [
        [
              {
                "mp4": "media/video/01.mp4",
                "quality": "720p"
              },
              {
                "mp4": "media/video/01_hd.mp4",
                "quality": "1080p"
              },
        ],
        [
              {
                "mp4": "media/video/02.mp4",
                "quality": "SD"
              },
              {
                "mp4": "media/video/02_hd.mp4",
                "quality": "HD"
              },
        ],
]

我开始做一些事情，但还不太接近：

var key, new_key, value,j=0, z=0, parr = [], obj;
for(var i = 0;i<a.length;i++){
    console.log('item:' ,a[i])
    key = a[i].key, value = a[i].value
    if(key.indexOf('path-'+j.toString()) > -1){
        new_key = key.substr(key.lastIndexOf('-')+1)
        console.log(key, new_key, value)
        for(var z = 0;z<value.length;z++){
            parr.push({[new_key]: value[z] })
        }
    }
}

console.log(parr)

[
  {
    "mp4": "media/video/01.mp4"
  },
  {
    "mp4": "media/video/01_hd.mp4"
  },
  {
    "quality": "720p"
  },
  {
    "quality": "1080p"
  }
]

编辑：

数组可以以相同的方式保存需要分组的不同键，例如：

    var arr = [
  {
    "key": "path-0-mp4",
    "value": [
      "media/video/01.mp4",
      "media/video/01_hd.mp4"
    ]
  },
  {
    "key": "path-0-quality",
    "value": [
      "720p",
      "1080p"
    ]
  },
  {
    "key": "path-1-mp4",
    "value": [
      "media/video/02.mp4",
      "media/video/02_hd.mp4"
    ]
  },
  {
    "key": "path-1-quality",
    "value": [
      "SD",
      "HD"
    ]
  },
  {
    "key": "subtitle-0-label",
    "value": [
      "English",
      "German",
      "Spanish"
    ]
  },
  {
    "key": "subtitle-0-src",
    "value": [
      "data/subtitles/sintel-en.vtt",
      "data/subtitles/sintel-de.vtt",
      "data/subtitles/sintel-es.vtt"
    ]
  },
  {
    "key": "subtitle-1-label",
    "value": [
      "German",
      "Spanish"
    ]
  },
  {
    "key": "subtitle-1-src",
    "value": [
      "data/subtitles/tumblr-de.vtt",
      "data/subtitles/tumblr-es.vtt"
    ]
  }
]

这是所需的结果(为每个不同的键创建新数组)：

 var arr = [
        [
              {
                "mp4": "media/video/01.mp4",
                "quality": "720p"
              },
              {
                "mp4": "media/video/01_hd.mp4",
                "quality": "1080p"
              },
        ],
        [
              {
                "mp4": "media/video/02.mp4",
                "quality": "SD"
              },
              {
                "mp4": "media/video/02_hd.mp4",
                "quality": "HD"
              },
        ],
],
arr2 = [        
    [
        {
            "label": "English",
            "src": "data/subtitles/sintel-en.vtt",
        },
        {
            "label": "German",
            "src": "data/subtitles/sintel-de.vtt"
        },
        {
            "label": "Spanish",
            "src": "data/subtitles/sintel-es.vtt"
        }
    ],
    [
        {
            "label": "Spanish",
            "src": "data/subtitles/tumblr-es.vtt",
        },
        {
            "label": "German",
            "src": "data/subtitles/tumblr-de.vtt"
        }
    ]
 ]

Answer 1

您可以拆分key属性，省略第一个path，并将其作为索引和键。然后创建一个新数组(如果不存在)并赋值。

​

var data = [{ key: "path-0-mp4", value: ["media/video/01.mp4", "media/video/01_hd.mp4"] }, { key: "path-0-quality", value: ["720p", "1080p"] }, { key: "path-1-mp4", value: ["media/video/02.mp4", "media/video/02_hd.mp4"] }, { key: "path-1-quality", value: ["SD", "HD"] }],
    result = data.reduce((r, { key, value }) => {
        let [, i, k] = key.split('-');
        r[i] = r[i] || [];
        value.forEach((v, j) => (r[i][j] = r[i][j] || {})[k] = v);
        return r;
    }, []);

console.log(result);

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​

如果您喜欢按key的第一部分进行分组，您可以使用这个组作为键的对象，并按上面的方式分配其余的对象。

​

var data = [{ key: "path-0-mp4", value: ["media/video/01.mp4", "media/video/01_hd.mp4"] }, { key: "path-0-quality", value: ["720p", "1080p"] }, { key: "path-1-mp4", value: ["media/video/02.mp4", "media/video/02_hd.mp4"] }, { key: "path-1-quality", value: ["SD", "HD"] }, { key: "subtitle-0-label", value: ["English", "German", "Spanish"] }, { key: "subtitle-0-src", value: ["data/subtitles/sintel-en.vtt", "data/subtitles/sintel-de.vtt", "data/subtitles/sintel-es.vtt"] }, { key: "subtitle-1-label", value: ["German", "Spanish"] }, { key: "subtitle-1-src", value: ["data/subtitles/tumblr-de.vtt", "data/subtitles/tumblr-es.vtt"] }],
    result = data.reduce((r, { key, value }) => {
        let [group, i, k] = key.split('-');
        if (!r[group]) r[group] = [];
        if (!r[group][i]) r[group][i] = [];
        value.forEach((v, j) => {
            if (!r[group][i][j]) r[group][i][j] = {};
            r[group][i][j][k] = v;
        });
        return r;
    }, {});

console.log(result);

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​

Answer 2

我是新手，是新手，这是正确的方法吗？

​

const a = [{ "key": "path-0-mp4", "value": [ "media/video/01.mp4", "media/video/01_hd.mp4" ] }, { "key": "path-0-quality", "value": [ "720p", "1080p" ] }, { "key": "path-1-mp4", "value": [ "media/video/02.mp4", "media/video/02_hd.mp4" ] }, { "key": "path-1-quality", "value": [ "SD", "HD" ] } ];

var resp = [];
for (let i = 0; i < a.length; i++) {
  var inst = a[i];
  var key = inst["key"];
  for (let j = 0; j < inst.value.length; j++) {
    var index = key.split("-")[1];
    var keyinst = key.split("-")[2];
    if (!resp[index]) {
      resp[index] = [];
    }
    if (!resp[index][j]) {
      resp[index][j] = {};
    }
    resp[index][j][keyinst] = inst.value[j];
  }
}
console.log(resp);

​

Answer 3

我觉得这更容易阅读和掌握

如果使用减缩，则可以保存赋值。

​

const arr = [{ "key": "path-0-mp4", "value": [ "media/video/01.mp4", "media/video/01_hd.mp4" ] }, { "key": "path-0-quality", "value": [ "720p", "1080p" ] }, { "key": "path-1-mp4", "value": [ "media/video/02.mp4", "media/video/02_hd.mp4" ] }, { "key": "path-1-quality", "value": [ "SD", "HD" ] } ];

newArr = [];
arr.filter(item => item.key.endsWith("mp4"))
     .forEach(item => item.value
       .forEach((val, i) => newArr.push({
          "mp4": val, 
      "quality": arr.find(qItem => qItem.key === item.key.replace("mp4", "quality")).value[i]}
     )
   )
 )

console.log(newArr)

​

这是妮娜的版本，没有混淆的版本

​

var data = [{ key: "path-0-mp4", value: ["media/video/01.mp4", "media/video/01_hd.mp4"] }, { key: "path-0-quality", value: ["720p", "1080p"] }, { key: "path-1-mp4", value: ["media/video/02.mp4", "media/video/02_hd.mp4"] }, { key: "path-1-quality", value: ["SD", "HD"] }],

  result = data.reduce((resultArray, { key, value }) => {
        let [, idx, suffix] = key.split('-');
        resultArray[idx] = resultArray[idx] || [];
        value.forEach((val, i) => (resultArray[idx][i] = resultArray[idx][i] || {})[suffix] = val);
        return resultArray;
    }, []);

console.log(result);

​