python游戏-多人游戏

Question

我正试图为来自不同计算机的至少三个参与者创建一个“画图”游戏。

我有一个对两个人有效的密码。有人知道我怎么能做到三人或更多人吗？

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以下是我的服务器代码：

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server = ""
port = 5555

games = {}
idCount = 0
currentPlayer = 0

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

s.bind((server, port))

s.listen()
print("Waiting for a connection, Server Started")

class Game:
    def __init__(self, id):
        self.connected = False

players = [Player(0), Player(1)]

def threaded_client(conn, player, gameId):
    global idCount
    conn.send(pickle.dumps(players[player]))
    reply = ""
    while True:
        try:
            data = pickle.loads(conn.recv(2048))
            players[player] = data
            if gameId in games:
                game = games[gameId]
                if not data:
                    print("Disconnected")
                    break
                else:
                    if player == 1:
                        reply = players[0]
                    else:
                        reply = players[1]

                conn.sendall(pickle.dumps(reply))
        except:
            break

    print("Lost connection")
    try:
        del games[gameId]
        print("Closing game", gameId)
    except:
        pass
    idCount -= 1
    conn.close()

while True:
    conn, addr = s.accept()
    print("Connected to:", addr)

    idCount += 1
    p = 0

    gameId = (idCount - 1) // 2

    if idCount % 2 == 1:
        games[gameId] = Game(gameId)
        players[0].connected = True
        print("Creating a new game")
        print("Waiting for another player")
    else:
        games[gameId].connected = True
        p = 1
        players[1].connected = True
        print("Game is available")



    start_new_thread(threaded_client, (conn, currentPlayer, gameId))
    currentPlayer += 1

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(谢谢:) :)

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Answer 1

您可以做的是，当一个游戏与两个玩家一起运行，而第三个玩家加入时，向他们展示等待更多玩家的屏幕，然后当第四个玩家加入时，运行一个新的线程/实例，并让服务器处理新的实例。

，但使用功能强大的pc来运行服务器，因为如果很多人加入服务器，由于overloading+，您运行的pc会导致服务器崩溃，服务器可能会滞后。