如何保存循环中的子流程的输出(json文件

Question

此代码发送将生成一个随机的json文件，其中包含所提供的用户ids和btw范围。

因此，此代码为每个用户输出50个json。

import faker
import json
from faker import Faker
import random
from random import randint
import subprocess
import json
import os
#subprocess.call([""])
from pprint import pprint

ids= ('5cda','6cda')

fake = Faker('en_US')

for ind in ids:
    cont = []
    #Overall dictionary with first and user_ids
    dct = {}
    for idx in range(50):

        sms =  {
            "id":"AB-asfgw",
            "body": fake.text(),
            "mime": fake.ean(),
            "hashed": fake.ean(),
            "pid": fake.ean(),
            "user_id": ind,
            "text": fake.sentence()
        }
        cont.append(sms)

    dct['messages'] = cont
    dct['user_id'] = ind
    #print(dct)
    f_name = '{}.json'.format(ind)
    with open(f_name, 'w') as fp:
        #Save the dictionary
        json.dump(dct, fp, indent=4)
        print('saved {}'.format(f_name))    

auth = "authorization: token 1324"
file = "5cda.json"
fd=open("5cda.json")
json_content = fd.read()
fd.close()


subprocess.run(["grpcurl", "-plaintext","-H", auth,"-d",json_content,"-format","json","100.20.20.1:5000","api.Service/Method"])

此loop.py代码循环第一个代码20次

from datetime import datetime
import faker
import json
from faker import Faker
import random
from random import randint
import subprocess
import json
import os
#subprocess.call([""])
from pprint import pprint
import subprocess
import sys



for i in range(20):
    subprocess.call(['python','grploop1.py'])

我需要为每个循环保存loop.py代码的输出。并存储该json。示例:我们在loop.py中循环第一个代码20次，因此存储的输出应该类似于5cda1.json .5cda20.json和6cda1.json.6cda20.json

这里我们给出了两个用户ids ids= ('5cda','6cda')，因此输出将总共是40个json文件。

Answer 1

您可能希望将文件保存逻辑放在for ind in ids:循环中，并在整个循环中使用索引来保存具有不同名称的文件。

import faker
import json
from faker import Faker
import random
from random import randint
import subprocess
import json
import os
#subprocess.call([""])
from pprint import pprint

ids= ('5cda','7f36')

fake = Faker('en_US')

msg_list = []

#Overall loop to run inner loop 20 times
for i in range(20):
    #Loop to generate messages
    for ind in ids:
        cont = []
        #Overall dictionary with first and user_ids
        dct = {}
        for idx in range(20):


            sms =  {
                "id":"AB-Iasd",
                "body": fake.sentence(),
                "reae": fake.ean(),
                "ashe": fake.ean(),
                "id2": fake.ean(),
                "user_id": ind,
                "pid": fake.sentence()
            }
            cont.append(sms)
        #Use a dictionary to save cont list to first key, and ind to user_ids key
        dct['messages'] = cont
        dct['user_id'] = ind
        msg_list.append(dct)

        #Append the index to the file here, and save the file
        f_name = '{}{}.json'.format(ind,i+1)
        with open(f_name, 'w') as fp:
            # Save the dictionary
            json.dump(dct, fp, indent=4)
            print('saved {}'.format(f_name))

您将获得40个文件，根据您的要求，在所有文件的独特内容。

Answer 2

如果您将J-son写入到STDOUT中，并且在loop.py中将STDOUT重定向到文件，则可以将被调用的python文件的输出保存到一个文件中。在你的“生成器”文件中：(当然，如果你不想得到无效的J-son文件，你应该删除其他打印。)

...
dct['messages'] = cont
dct['user_id'] = ind
print(dct)
...

在loop.py文件中：

subprocess.call(["ardbuf", "-oL", "python","grploop1.py", ">", test_folder/tmp_file.json])