我使用array_intersect比较两个数组
$myArray = array(
array(
'site_id' => 'S6407',
'tssr_id' => 'TSSRBOQ-200204-0145-59'
),
array(
'site_id' => 'S5910',
'tssr_id' => 'TSSRBOQ-200204-0145-8'
),
);
// $items_tssr is get from another variable
foreach ($items_tssr as $key => $value) {
$array_validate[] = array(
'site_id' => $value['site_id'],
'tssr_id' => $value['no_tssr_boq_site']
);
}
$result = array_map('unserialize',
array_intersect(
array_map('serialize', $myArray), array_map('serialize', $array_validate)));
// if there are same
if(array_key_exists(0,$result)){
echo 'process this';
}else{
echo 'dont process this';
}我的问题是,原来的$myArray不仅仅是site_id和tssr_id
$myArray_origin = array(
'site_id' => 'S6407',
'tssr_id' => 'TSSRBOQ-200204-0145-59'
'site_name' => 'Site S6407',
'id_site_doc'=> '127361,
'implementation_id' => 'imp4121',
'status' => "implementation_created",
"endstate" => false
),
...如何在不丢弃一些值的情况下处理$myArray_origin?因为$array_validate只有两个值'site_id‘和'tssr_id’
发布于 2020-04-18 06:10:34
您可以使用array_filter + in_array代替。这将只保留site_id和tssr_id存在于array_validate自己的条目中的条目:
$result = array_filter($myArray, function (array $entry) use ($array_validate): bool {
return in_array([
'site_id' => $entry['site_id'],
'tssr_id' => $entry['tssr_id']
], $array_validate, true);
});演示:
https://stackoverflow.com/questions/61284762
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