如何将对象的对象转换为单独的值。

Question

我试图从JSON调用中访问信息，以便将数据存储到数组中并进一步使用它。这是一个API调用示例API的示例。我正在尝试访问“爱奇”概率，这是一个对象的对象。我需要它的整数值，比如9，53，10,102.等等，我编写了以下代码，将其转换为一个名为dataArray的对象数组，然后对其进行进一步的迭代以获得分离的键: value对。

 const dataArray = Object.values(response.body.data.iaqi);
        const iterator = dataArray.entries();

        for(const[index, element] of iterator){
            console.log(element)
        }

这给了我以下的输出:-

输出

有任何方法可以访问单个数字值并将它们存储在数组中吗？任何帮助都将不胜感激，如果我做错了什么，请纠正我，我是新来的。

Answer 1

你是说，像那样？

​

const src = {"status":"ok","data":{"aqi":137,"idx":1451,"attributions":[{"url":"http://www.bjmemc.com.cn/","name":"Beijing Environmental Protection Monitoring Center (北京市环境保护监测中心)"},{"url":"https://china.usembassy-china.org.cn/embassy-consulates/beijing/air-quality-monitor/","name":"U.S Embassy Beijing Air Quality Monitor (美国驻北京大使馆空气质量监测)"},{"url":"https://waqi.info/","name":"World Air Quality Index Project"}],"city":{"geo":[39.954592,116.468117],"name":"Beijing (北京)","url":"https://aqicn.org/city/beijing"},"dominentpol":"pm25","iaqi":{"co":{"v":5.5},"h":{"v":54},"no2":{"v":13.3},"o3":{"v":57.1},"p":{"v":1002},"pm10":{"v":80},"pm25":{"v":137},"so2":{"v":2.1},"t":{"v":27},"w":{"v":3.6}},"time":{"s":"2020-05-02 00:00:00","tz":"+08:00","v":1588377600},"debug":{"sync":"2020-05-02T01:17:30+09:00"}}},

      result = Object
        .values(src.data.iaqi)
        .map(Object.values)
        .flat()
        
console.log(result)

.as-console-wrapper{min-height:100%;}

​

如果您的内部对象具有静态结构(单个v键)，则可能会稍微缩短上面的内容。

​

const src = {"status":"ok","data":{"aqi":137,"idx":1451,"attributions":[{"url":"http://www.bjmemc.com.cn/","name":"Beijing Environmental Protection Monitoring Center (北京市环境保护监测中心)"},{"url":"https://china.usembassy-china.org.cn/embassy-consulates/beijing/air-quality-monitor/","name":"U.S Embassy Beijing Air Quality Monitor (美国驻北京大使馆空气质量监测)"},{"url":"https://waqi.info/","name":"World Air Quality Index Project"}],"city":{"geo":[39.954592,116.468117],"name":"Beijing (北京)","url":"https://aqicn.org/city/beijing"},"dominentpol":"pm25","iaqi":{"co":{"v":5.5},"h":{"v":54},"no2":{"v":13.3},"o3":{"v":57.1},"p":{"v":1002},"pm10":{"v":80},"pm25":{"v":137},"so2":{"v":2.1},"t":{"v":27},"w":{"v":3.6}},"time":{"s":"2020-05-02 00:00:00","tz":"+08:00","v":1588377600},"debug":{"sync":"2020-05-02T01:17:30+09:00"}}},

      result = Object
        .values(src.data.iaqi)
        .map(({v}) => v)
        
console.log(result)

.as-console-wrapper{min-height:100%;}

​

Answer 2

我在使用for...in时做了一些工作。遍历所有对象条目并打印出v的值。

​

var dataArray = {
  co: {
  v: 4.6
  },
  h: {
  v: 54
  },
  no2: {
  v: 9.2
  },
  o3: {
  v: 46.3
  },
  p: {
  v: 1002
  },
  pm10: {
  v: 70
  },
  pm25: {
  v: 137
  },
  so2: {
  v: 1.6
  },
  t: {
  v: 26
  },
  w: {
  v: 3.6
  }
}
for(const element in dataArray){
    console.log(dataArray[element]['v'])
}

​