Spring升级到2.2.6 -无法将yaml属性绑定到对象列表

Question

我正在将一个项目升级到SpringBoot2.2.6。以下是wrt将yaml属性数据绑定到对象列表的编译错误-

**请注意，该项目正在编译以前版本的spring (2.2.1)，我一直在使用**。

org.springframework.boot.context.properties.ConfigurationPropertiesBindException:错误创建名为“webUiApplication.state”的bean :无法将属性绑定到“WebUiApplication.States”：prefix=states、ignoreInvalidFields=false、ignoreUnknownFields=true；嵌套异常是org.springframework.boot.context.properties.bind.BindException:未能将属性绑定到java.util.List下

application.yml

   states:
  defaults:
    -
      postal-code: AL
      name: Alabama
    -
      postal-code: AK
      name: Alaska
    -
      postal-code: AZ
      name: Arizona

配置

    @Data 
   @Configuration
   @ConfigurationProperties("states")
   public static class States {

      private List<State> defaults;

      private List<State> docVerify;

      private List<State> registration;

  }

波霍

@Data
@EqualsAndHashCode(onlyExplicitlyIncluded = true)
@ToString(onlyExplicitlyIncluded = true)
public class State implements ListOption {
   public static final Comparator<State> DISPLAY_COMPARATOR = new ListOption.DisplayComparator<>();

   @NonNull private final String postalCode;

   @NonNull private final String name;

@Override
   @EqualsAndHashCode.Include
   public String getValue() {
      return this.postalCode;
   }

   @Override
   @ToString.Include
   public String getLabel() {
      return String.format("%s - %s", postalCode, name);
   }
}

曾遇到议员收到类似问题但未能找到解决办法的职位。期待您的投入。

Answer 1

重构代码：

各国：

@Data

    @Configuration
    @ConfigurationProperties("states")
    @ToString
    @NoArgsConstructor
    public class States {
        private List<State> defaults;
        private List<State> docVerify;
        private List<State> registration;

    }

状态：

@Data
@EqualsAndHashCode(onlyExplicitlyIncluded = true)
@ToString(onlyExplicitlyIncluded = true)
@NoArgsConstructor
public class State {
    @NonNull
    private String postalCode;

    @NonNull
    private String name;

    @EqualsAndHashCode.Include
    public String getValue() {
        return this.postalCode;
    }

    @ToString.Include
    public String getLabel() {
        return String.format("%s - %s", postalCode, name);
    }
}

application.yaml

states:
  defaults:
    -
      postal-code: AL
      name: Alabama
    -
      postal-code: AK
      name: Alaska
    -
      postal-code: AZ
      name: Arizona

我们需要一个空对象，然后用数据填充它。这就是为什么我们不需要args构造函数。