提取(.*)信息的Regex

Question

编辑：

实际例子：

@george Hi, I want to buy your car listed for 2500 in Seattle.

我想救出乔治，车，2500，西雅图。用findall我达到了这个阶段

re.findall("(.*)Hi, I want to buy your (.*) listed for (.*) in (.*)",buy)

它返回一个包含所有发现的元组。

output: ('@george ', 'car', '2500', 'Seattle.')

我尝试使用.split("，")，但它返回一个'tuple‘对象没有属性’拆分‘。

Answer 1

您可以使用re.search进行第一次匹配，并且可以使用match.groups()访问所有组。

import re
buy = r'@george Hi, I want to buy your car listed for 2500 in Seattle.'
m = re.search(r"(.*)Hi, I want to buy your (.*) listed for (.*) in (.*)",buy)
for g in m.groups():
    print(g)

见Python演示。输出：

@george 
car
2500
Seattle.