如何在SpringBoot中获取Rsocket连接的远程IP地址

Question

我正在尝试获取连接到RSocket+SpringBoot get服务器的浏览器的远程IP。连接是RSocket之上的WebSocket。

and服务器是Java-8，SpringBoot-2，使用RSocket over WebSocket并向浏览器发送RequestStreams。我正在利用SpringBoot自动配置来设置RSocket，所以服务器端的代码非常少-参见下面。

下面代码中的@Headers and MessageHeader只是看看他们是否有任何东西可以导致远程IP，而没有其他原因。

我在网上搜索过答案--很多是http，一些是websockets，0是RSocket。这个-- https://github.com/rsocket/rsocket-java/issues/735 --看上去很有希望，但没能拿到DuplexConnection的手柄，所以那里没有雪茄。

有什么想法吗？太棒了！

application.yml:

spring.rsocket.server:
  mapping-path: /rsocket-test
  transport: websocket

server.port: 8080

TestController.java

 /**
     * TODO: get the remote IP address and log.
     * Options:
     * 1. @see <a href="https://github.com/rsocket/rsocket-java/issues/735">Ability to intercept requests and access channel information such as remote address</a>.
     * 2. Inject IP in header by nginx. See if it shows up in the @Headers param here.
     * 3. Browser gets its public IP and adds it to the request object. Doable, but lame
     * 4. (Unlikely) Find a way to access thru this chain of private members: headers.req.rsocket().source.connection.source.connection.connection.channel.remoteAddress
     */
    @MessageMapping("subscribe-topic")
    public Flux<StreamingEvent> subscribeToEventStream(
                @Headers Map<String,Object> hdrs,
                MessageHeaders mh,
                testRequest request) {
        return testService.subscribeTopic(request.getRequestId(), request.getTopic());
    }

Answer 1

客户端的ip地址在DuplexConnection类中可用。您可以向RSocketServer添加一个拦截器，如下所示：

@Bean
public RSocketServerCustomizer ipCustomizer() {
    return rSocketServer -> rSocketServer.interceptors(registry -> registry.forConnection(new ConnectionInterceptor()));
}

其中ConnectionInterceptor是：

static class ConnectionInterceptor implements DuplexConnectionInterceptor {
    @Override
    public DuplexConnection apply(Type type, DuplexConnection duplexConnection) {
        SocketAddress socketAddress = duplexConnection.remoteAddress();
        if (socketAddress instanceof InetSocketAddress) {
            InetSocketAddress iso = (InetSocketAddress) socketAddress;
            // Here is the ip: iso.getHostString()
        }
        return duplexConnection;
    }
}

Answer 2

在我的场景中，我希望将远程主机和原始HTTP请求头传递给我的@MessageMapping处理程序。我想出的最佳方法是创建自己的NettyRouteProvider并使用所需的数据丰富订阅上下文：

@Component
public class MyRouteProvider implements NettyRouteProvider {

    private final String mappingPath;
    private final SocketAcceptor socketAcceptor;
    private final List<RSocketServerCustomizer> customizers;

    @Autowired
    MyRouteProvider(RSocketProperties properties, RSocketMessageHandler messageHandler,
                    ObjectProvider<RSocketServerCustomizer> customizers) {
        this.mappingPath = properties.getServer().getMappingPath();
        this.socketAcceptor = messageHandler.responder();
        this.customizers = customizers.orderedStream().collect(Collectors.toList());
    }

    @Override
    public HttpServerRoutes apply(HttpServerRoutes httpServerRoutes) {
        RSocketServer server = RSocketServer.create(this.socketAcceptor);
        this.customizers.forEach((customizer) -> customizer.customize(server));
        ServerTransport.ConnectionAcceptor connectionAcceptor = server.asConnectionAcceptor();

        return httpServerRoutes.ws(this.mappingPath, (in, out) ->
                connectionAcceptor.apply(new WebsocketDuplexConnection((Connection) in)).then(out.neverComplete())
                        .contextWrite(context -> {
                            String ip = in.headers().get("x-forwarded-for");
                            SocketAddress remoteAddress = ((Connection) in).channel().remoteAddress();
                            
                            if(in.headers().contains("x-forwarded-for")){
                                return context
                                        .put("remoteHost",remoteAddress)
                                        .put(HttpHeaders.class, in.headers())
                                        .put("client-ip", ip);
                            }
                            return context
                                    .put("remoteHost",remoteAddress)
                                    .put(HttpHeaders.class, in.headers());
                        }));
    }

}

在此之后，您将能够在任何@MessageMapping方法中从上下文中获取数据，例如：

@MessageMapping("remote-host")
fun remoteHost(): Mono<SocketAddress> {
    return Mono.deferContextual { context ->
        Mono.just(context.get<SocketAddress>("remoteHost"))
    }
}

Answer 3

我和这个问题斗争了一段时间。我不喜欢接受的答案，因为没有办法将信息传递给处理程序。Nokina的回答是有效的，但只适用于最初的请求。对于随后的请求，上下文将不包含地址。花了几个小时之后，我又回到了正确的反思中，想出了这样的想法：

import io.rsocket.DuplexConnection;
import io.rsocket.RSocket;
import org.springframework.messaging.rsocket.RSocketRequester;
import org.springframework.util.ReflectionUtils;

import java.lang.reflect.Field;
import java.net.SocketAddress;

public class RSocketUtil {

    public static DuplexConnection getConnectionFromRequester(RSocketRequester requester) {
        RSocket rsocket = requester.rsocket();
        Field connectionField = ReflectionUtils.findField(rsocket.getClass(), "connection");
        connectionField.setAccessible(true);
        return (DuplexConnection) ReflectionUtils.getField(connectionField, rsocket);
    }

    public static SocketAddress getRemoteAddressFromRequester(RSocketRequester requester) {
        DuplexConnection connection = getConnectionFromRequester(requester);
        return connection.remoteAddress();
    }

}