根据另一个DF列中的值选择DF

Question

我想绑定两个数据文件的列。根据第一个dataframe中单元格的值，应该在我的环境中的几个数据文件中选择第二个dataframe。

样本数据

test <- structure(list(main_activity = structure(c(1L, 9L), .Label = c("Manufacturing", 
"Manufacturing; Retail", "Manufacturing; Services", "Manufacturing; Wholesale", 
"Manufacturing; Wholesale; Services", "Retail", "Retail; Services", 
"Retail; Wholesale", "Services", "Services; Manufacturing", "Services; Retail", 
"Services; Wholesale", "Wholesale", "Wholesale; Manufacturing", 
"Wholesale; Retail", "Wholesale; Services"), class = "factor"), 
    p_l_for_period_net_income_th_eur_2019 = c(-4849.968, -4416.404
    ), Name = c("A", "B")), class = "data.frame", row.names = c(NA, 
-2L))

Manufacturing_2015 <- as.data.frame(matrix(data = c(2000)))
Services_2015 <- as.data.frame(matrix(data = c(3000)))

我想要做的是检查列'main_activity‘的值，并将与该名称匹配的dataframe与'test’数据name绑定。因此，我们的目标是实现以下目标：

期望结果

binded_A <- cbind(test %>% filter(Name == "A"), Manufacturing_2015)
binded_B <- cbind(test %>% filter(Name == "B"), Services_2015)

有办法自动完成吗？

Answer 1

您可以使用ls从全局环境中根据其在main_activity中的值选择数据帧，并将数据转换为原始数据子集。

result <- lapply(test$main_activity, function(x) cbind(subset(test, 
               main_activity == x), get(ls(pattern = x, envir = .GlobalEnv))))

result

#[[1]]
#  main_activity p_l_for_period_net_income_th_eur_2019 Name   V1
#1 Manufacturing                             -4849.968    A 2000

#[[2]]
#  main_activity p_l_for_period_net_income_th_eur_2019 Name   V1
#2      Services                             -4416.404    B 3000

这将返回一个数据文件列表，如果您需要它们作为单独的dataframes命名并使用list2env。

names(result) <- paste0('binded_', test$Name)
list2env(result, .GlobalEnv)