我需要制定一个mysql查询,以选择以这种方式标准化的值:normalized = (value-min(values))/(max(values)-min(values)),我的尝试如下所示:
select
Measurement_Values.Time,
((Measurement_Values.Value-min(Measurement_Values.Value))/(max(Measurement_Values.Value)-min(Measurement_Values.Value)))
from Measurement_Values
where Measurement_Values.Measure_ID = 49 and Measurement_Values.time >= '2020-05-30 00:00'但显然是错误的,因为它只返回一个值。你能帮我找到正确的语法吗?
发布于 2020-06-05 09:59:28
您的问题解释得有点少,但我认为您需要窗口函数(仅在MySQL 8.0中提供):
select
time,
value,
(value - min(value) over() / (max(value) over() - min(value) over()) normalized_value
from measurement_values
where measure_id = 49 and time >= '2020-05-30 00:00'或者,在早期版本中,可以通过使用聚合查询连接表获得相同的结果:
select
mv.time,
mv.value,
(mv.value - mx.min_value) / (mx.max_value - mx.min_value) normalized_value
from measurement_values
cross join (
select min(value) min_value, max(value) max_value
from measurement_values
where measure_id = 49 and time >= '2020-05-30 00:00'
) mx
where measure_id = 49 and time >= '2020-05-30 00:00'https://stackoverflow.com/questions/62211117
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