使用kotlin编写聊天应用程序,历史上使用nodejs,我有/output格式的websocket对象:
{"action": "join:chatroom", "payload", "chatroom-name"}
{"action": "leave:chatroom", "payload", "chatroom-name"}
{"action": "message", "payload", {"id": 1, "text": "blah", "user": {"name": "Roman"}}}
{"action": "notification", "payload", {"id": 1, "verb": "blah", "user": {"name": "Roman"}}}尝试采用kotlinx序列化,以便能够在没有运气的情况下使用这种方法,似乎sealed class是我可以尝试的最接近的方法,但是如何将type更改为action。
采用这种方法,https://ahsensaeed.com/sealed-classes-kotlinx-serialization-deserialization/试图执行如下操作:
@Polymorphic
@Serializable
sealed class BackendAction{
@Serializable
data class Auth(
// val action: String = "authorize",
val payload: String = ""
) : BackendAction()
}
class BackendActionSerializer {
private val sealedModule = SerializersModule {
polymorphic(BackendAction::class) {
BackendAction.Auth::class with BackendAction.Auth.serializer()
}
}
private val serializer: KSerializer<BackendAction>
get() = BackendAction.serializer()
val format: StringFormat
get() = Json(configuration = JsonConfiguration(classDiscriminator = "action"), context = sealedModule)
fun toStringT(json: String): BackendAction {
return format.parse(serializer, json)
}
fun toTString(t: BackendAction): String {
return format.stringify(serializer, t)
}
}然后打电话:
val act = BackendAction.Auth("blah")
val serializer = BackendActionSerializer()
val data = serializer.toTString(act)给出{"action":"com.project.path.BackendAction.Auth","payload":"blah"},所以我需要将com.project.path.BackendAction.Auth映射到authorize
编辑:
回答我的问题:@SerialName("authorize")很简单:)
@Polymorphic
@Serializable
sealed class BackendAction{
@Serializable
@SerialName("authorize")
data class Auth(
var payload: String = ""
) : BackendAction()
}这个聊天应用程序的web用户界面工作在这里:https://www.lonje.com/
发布于 2020-06-08 05:22:16
@SerialName("authorize")做到了这一点
@Polymorphic
@Serializable
sealed class BackendAction{
@Serializable
@SerialName("authorize")
data class Auth(
var payload: String = ""
) : BackendAction()
}https://stackoverflow.com/questions/62249319
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