因此,名为“options”的字典显示了strike_price、ask_price、delta和implied_volatility下面的结果(可交易选项)。但我不需要它来说出所有可交易的选择。我只想让输出显示一个具有最高implied_volatility (IV)的可交易选项,因此,例如,结果应该只显示具有最高IV的选项:
罢工价格: 43.0000,要求: 0.030000,出价: 0.000000,三角洲: 0.008705,IV: 1.449510 -因为IV是从整个产量以下的最高。
我该怎么做?
import config
import robin_stocks as r
r.login(config.USERNAME,config.PASSWORD)
#specify criteria to search for options of a given symbol and its exp date
symbol = 'GDX'
expirationDate = '2020-06-19'
search_option = r.find_options_for_stock_by_expiration(symbol,expirationDate,optionType='call')
for option in search_option:
print("Strike Price: {}, Ask: {}, Bid: {}, Delta: {}, IV: {}".format(option['strike_price'],option['ask_price'],option['bid_price'],option['delta'], option['implied_volatility']))
**OUTPUT**:
Strike Price: 42.0000, Ask: 0.030000, Bid: 0.000000, Delta: 0.009354, IV: 1.335719
Strike Price: 43.0000, Ask: 0.030000, Bid: 0.000000, Delta: 0.008705, IV: 1.449510
Strike Price: 35.5000, Ask: 0.060000, Bid: 0.040000, Delta: 0.073395, IV: 0.634361
Strike Price: 36.5000, Ask: 0.030000, Bid: 0.020000, Delta: 0.041370, IV: 0.743600发布于 2020-06-17 17:58:23
替换代码的for循环,替换这个循环。
highest_IV, highest_idx = 0, None
for idx, option in enumerate(search_option):
if option['implied_volatility'] and highest_IV < float(option['implied_volatility']):
highest_IV = float(option['implied_volatility'])
highest_idx = idx
if highest_idx is not None:
print("Strike Price: {strike_price}, Ask: {ask_price}, Bid: {bid_price}, Delta: {delta}, IV: {implied_volatility}".format(**search_option[highest_idx]))在这里,您可能需要考虑search_option为空的情况。
我希望这能帮到你。
发布于 2020-06-17 17:49:08
您可以在最高的IV执行如下操作时返回该选项:
def find_highest_iv(search_option):
max_iv = max([option['implied_volatility'] for option in search_option ])
for option in search_option:
for k,v in option.items():
if k == 'implied_volatility' and v == max_iv:
return option如果有两个具有相同IV的选项,这将返回在search_options中找到的第一个选项。也许还有一种更多的节能型速记方法可以做到这一点,但这应该是可行的。
https://stackoverflow.com/questions/62434946
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