我使用的是oracle,表中有重复的行,如下所示:
Month Product
March ENVOY & External Keyboard (22)
March ENVOY & External Keyboard (22)
March ENVOY & External Keyboard (22)
March ENVOY & External Keyboard (22)
March ENVOY & External Keyboard (22)
March ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)我需要把它变成这样的东西:
Month Product
March ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)我试着用SELECT (case when row_number() over (partition by times.calendar_month_name order by (select NULL)) = 1 then times.calendar_month_name end) Month,但不工作.有什么想法吗?
发布于 2020-06-20 11:57:53
您可以使用LAG()窗口函数:
select
nullif(Month, lag(Month) over (order by null)) Month,
Product
from tablename见演示。
结果:
> MONTH | PRODUCT
> :---- | :-----------------------------
> March | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> April | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)
> | ENVOY & External Keyboard (22)发布于 2020-06-20 12:12:28
SQL*Plus中的小菜一碟:
SQL> break on month
SQL>
SQL> select month, product from test order by month desc;
MONTH PRODUCT
---------- ------------------------------
March ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
April ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
ENVOY & External Keyboard (22)
11 rows selected.
SQL>发布于 2020-06-20 11:54:47
这种类型的操作在应用程序级别确实做得更好。您可以使用row_number(),但是您需要小心:
select (case when seqnum = 1 then month end) as month, product
from (select t.*,
row_number() over (partition by month order by month) as seqnum
from t
) t
order by month, seqnum;注意,SQL查询返回的结果是不确定的顺序。因此,您需要一个外部order by来保证排序(即“第一个”行具有该值)。因为您处理的是精确的重复,所以没有唯一的排序键,所以即使是对row_number()的两次调用也会产生不同的结果--因此可以使用子查询。
https://stackoverflow.com/questions/62485438
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