我想创造一个单一的视觉显示多个直方图在它上。我有一些简单的值数组,如下所示:
"data": {"values": {"foo": [0,0,0,1,1,1,2,2,2], "baz": [2,2,2,3,3,3,4,4,4]}}我想使用不同的颜色条来显示"foo“和"baz”的值的扩展。我可以为"foo“做一个直方图,如下所示:
{
"data": {"values": {"foo": [0,0,0,1,1,1,2,2,2]}},
"mark": "bar",
"transform": [{"flatten": ["foo"]}],
"encoding": {
"x": {"field": "foo", "type": "quantitative"},
"y": {"field": "foo", "type": "quantitative", "aggregate": "count"}
}
}但是,我无法找到正确的方法来平平数组。这不管用:
{
"data": {"values": {"foo": [0,0,0,1,1,1,2,2,2], "bar": [0,0,0,1,1,1,2,2,2]}},
"mark": "bar",
"transform": [{"flatten": ["foo", "baz"]}],
"encoding": {
"x": {"field": "foo", "type": "quantitative"},
"y": {"field": "foo", "type": "quantitative", "aggregate": "count"}
},
"layer": [{
"mark": "bar",
"encoding": {
"y": {"field": "baz", "type": "quantitative", "aggregate": "count"}
}
}]
}检查data_0时,foo和它的计数都有列,而baz则没有。
这也不起作用:
{
"data": {
"values": {
"foo": [0, 0, 0, 1, 1, 1, 2, 2, 2],
"baz": [0, 0, 0, 1, 1, 1, 2, 2, 2]
}
},
"mark": "bar",
"transform": [{"flatten": ["foo"]},{"flatten": ["baz"]}],
"encoding": {
"x": {"field": "foo", "type": "quantitative"},
"y": {"field": "foo", "type": "quantitative", "aggregate": "count"}
},
"layer": [
{
"mark": "bar",
"encoding": {
"y": {"field": "baz", "type": "quantitative", "aggregate": "count"}
}
}
]
}这仍然只给出了foo及其计数的列,但是现在每个桶的计数是27!
如何实现从数组数据开始的多直方图图形?
发布于 2020-07-06 23:44:11
您可以使用一个平坦变换和一个褶皱变换来完成这个任务,然后使用颜色编码来分离这两个数据集。例如(开放编辑器):
{
"data": {
"values": {
"foo": [0, 0, 1, 1, 1, 1, 2, 2, 2],
"baz": [4, 4, 5, 5, 6, 6, 6, 6, 7]
}
},
"transform": [{"flatten": ["foo", "baz"]}, {"fold": ["foo", "baz"]}],
"mark": "bar",
"encoding": {
"x": {"field": "value", "type": "quantitative"},
"y": {
"field": "value",
"type": "quantitative",
"aggregate": "count",
"stack": null
},
"color": {"field": "key", "type": "nominal"}
}
}

另外,如果将编码放在单独的层中,则层方法也可以工作,这样外部foo聚合不会破坏baz数据,但它比基于折叠的方法要详细一些
{
"data": {
"values": {
"foo": [0, 0, 1, 1, 1, 1, 2, 2, 2],
"baz": [4, 4, 5, 5, 6, 6, 6, 6, 7]
}
},
"transform": [{"flatten": ["foo", "baz"]}],
"layer": [
{
"mark": {"type": "bar", "color": "orange"},
"encoding": {
"x": {"field": "foo", "type": "quantitative"},
"y": {"field": "foo", "type": "quantitative", "aggregate": "count"}
}
},
{
"mark": "bar",
"encoding": {
"x": {"field": "baz", "type": "quantitative"},
"y": {"field": "baz", "type": "quantitative", "aggregate": "count"}
}
}
]
}https://stackoverflow.com/questions/62764869
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