循环数组: While循环和2D数组

Question

一些背景:这个程序读取石头的线条，并将它们放到地图上。

程序应该首先要求以整数的形式列出石头的行数。然后，程序将以下列格式将行的位置扫描为一个由四个整数组成的组：

行列长度值

行和列表示到地图上放置的块的水平线中最左边的块。长度告诉你在这条水平线上应该有多少块石头。在这个例子中，假设第四个整数总是1代表一个石头。

示例: CommandMeaning

0 0 5 1放置一行石头，从开始到结束。这条线上的所有5个方块将被设置为1(石头)。

我的问题是试图在长度方面进行编码，但我找不出模式：

• ，我们只允许使用we循环，对于循环不允许使用

。

#define SIZE 15
#define EMPTY 0
#define STONE 1

void printMap(int map[SIZE][SIZE], int playerX);


int main (void) {
    // This line creates our 2D array called "map" and sets all
    // of the blocks in the map to EMPTY.
    int map[SIZE][SIZE] = {EMPTY};


    // This line creates out playerX variable.
    int playerX = SIZE / 2;

    printf("How many lines of stone? ");
    int linesOfStone; 
    scanf("%d", &linesOfStone);

    printf("Enter lines of stone:\n");
 
    int rowPos; 
    int columnPos; 
    int stoneLength; 
    int stoneValue; 
   
    int i = 0; 
    while (i < linesOfStone) {
        scanf("%d %d %d %d", &rowPos, &columnPos, &stoneLength, &stoneValue); 
        map[rowPos][columnPos]++; //pos for position
      
//ERROR: This was my attempt to incorporate the length aspect, i think my logic got lost along the way... 
  
            int j = 0; 
            while (j < stoneLength) {
            rowPos++; 
            j++; 
            }
    i++; 
    }

    printMap(map, playerX);

    return 0;
}

// Print out the contents of the map array. Then print out the player line
// which will depends on the playerX variable.
void printMap(int map[SIZE][SIZE], int playerX) {
    
    // Print values from the map array.
    int i = 0;
    while (i < SIZE) {
        int j = 0;
        while (j < SIZE) {
            printf("%d ", map[i][j]);
            j++;
        }
        printf("\n");
        i++;
    }    
    
    // Print the player line.
    i = 0;
    while (i < player

Answer 1

将您的第二个while循环替换为下面一个：

for (int j=0; j < stoneLength; j++)  // Iterate over all affected map tiles
    map[rowPos + j][columnPos] = 1;  // Make this map tile STONE

这个集合将从[rowPos][columnPos]到[rowPos + stoneLength - 1][columnPos]的所有映射块