如何使用logitech lua脚本

Question

我试图有两个输入，这将导致一个输出。这样我就可以在游戏中使用一种能力，如果你能帮忙的话，谢谢。

function OnEvent(event, arg) 
     if event == "MOUSE_BUTTON_PRESSED" and arg == 2 then --set flag for mb2
            mb2_pressed = true
    elseif event == "MOUSE_BUTTON_RELEASED" and arg == 2 then --set flag for mb2=false
        mb2_pressed = false
    else if event == "LSHIFT_BUTTON_PRESSED" and arg == 1 then
    leftshift_pressed = true
    else if event == "LSHIFT_BUTTON_RELEASED" and arg == 1 then
    leftshift_pressed = false
    end
end

if leftshift_pressed and  if mb2_pressed then
presskey("9")
        Sleep(50)
        releasekey("9")
end
end

https://gyazo.com/7e7f2139fabb22d1e06f8f3f169cb4bb

Answer 1

function OnEvent(event, arg)
   if event == "MOUSE_BUTTON_PRESSED" and arg == 2 and IsModifierPressed("lshift") then
      PressAndReleaseKey("lshift")
      PressAndReleaseKey("9")
   end
end

你应该知道以下几点：

position)

• if leftshift_pressed and if mb2_pressed then LGS/GHUB在行编号上有一个错误，错误消息中的“第12行”实际上意味着代码中的line#13 (而红色条带也设置在错误的是语法错误，您应该编写if leftshift_pressed and mb2_pressed then
• if/elseif/else/end必须保持平衡。你的不是。在代码中使用缩进使其obvious.
• There不是事件LSHIFT_BUTTON_PRESSED，您只接收来自G-按钮的事件( Logitech鼠标上的所有按钮和Logitech keyboard).
• Uppercase上的特殊G-按钮都不同于小写：PressKey与presskey

不一样。