Matplotlib孪生y轴

Question

我想用y轴中间的0绘制我的数据。就像这样：

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这就是我想出来的：

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使用此代码：

import matplotlib.pyplot as plt

group_a_names = ['A', 'B', 'C', 'D', 'E']
group_a_values = [2, 4, 6, 8, 10]

group_b_names = ['F', 'G', 'H', 'I', 'J']
group_b_values = [1, 2, 3, 4, 5]

fig, ax1 = plt.subplots(figsize=(5, 4), dpi=100)
ax2 = ax1.twiny()

ax1.plot(group_a_names, group_a_values)
ax2.plot(group_b_names, group_b_values)

plt.show()

我怎样才能像第一张图像一样可视化我的数据？还可以在右边镜像y号的标签/标记？

Answer 1

我只是翻转了其他的值，并倒转负面标签。

import matplotlib.pyplot as plt

group_a_names = ['A', 'B', 'C', 'D', 'E']
group_a_values = [2, 4, 6, 8, 10]

group_b_names = ['F', 'G', 'H', 'I', 'J']
group_b_values = [1, 2, 3, 4, 5]
group_b_values_neg = list(map(lambda n: n * -1, group_b_values))

max_value = max(group_a_values + group_b_values)

fig = plt.figure()
ax1 = fig.add_subplot(1, 1, 1)
ax2 = ax1.twiny()
ax1.plot(group_a_names, group_a_values, c="blue")
ax2.plot(group_b_names, group_b_values_neg, c="red")

ax1.set_ylim(max_value * -1, max_value)
ax2.set_ylim(max_value * -1, max_value)
ax2.set_yticklabels([str(abs(x)) for x in ax2.get_yticks()])

ax1.yaxis.set_ticks_position('both')
ax1.tick_params(axis="y", labelright=True)

plt.show()

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Answer 2

这对我起了作用：

ticks = np.arange(2, 11, 2)
plt.yticks(ticks, [10, 5, 0, 5, 10])

ax1.yaxis.set_ticks_position('both')
ax1.tick_params(axis="y", labelright=True)

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Answer 3

试试这个：

import matplotlib.pyplot as plt
group_a_names = ['A', 'B', 'C', 'D', 'E']
group_a_values = [2, 4, 6, 8, 10]

group_b_names = ['F', 'G', 'H', 'I', 'J']
group_b_values = [-2, -4, -6, -8, -10]

fig, ax1 = plt.subplots(figsize=(5, 4), dpi=100)
ax1.plot(group_a_names, group_a_values)

# add second x axis
ax3 = ax1.twiny()
ax3.plot(group_b_names, group_b_values)

# add second y axis
ax2 = ax1.twinx()

# set y axis range
plt.ylim(-10, 10)

plt.show()

结果：

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