http4s解压缩压缩http响应

Question

我尝试在客户端解压缩gzipped简单响应。用http4s做这件事的合适方法是什么？

import cats.effect.{Blocker, ContextShift, IO, Timer}
import java.util.concurrent._
import org.http4s.{Header, Headers, HttpVersion, Method, Request}
import org.http4s.client.{Client, JavaNetClientBuilder}
import org.http4s.implicits._

import scala.concurrent.ExecutionContext.global
implicit val cs: ContextShift[IO] = IO.contextShift(global)
implicit val timer: Timer[IO] = IO.timer(global)

val blockingPool = Executors.newFixedThreadPool(5)
val blocker = Blocker.liftExecutorService(blockingPool)
val httpClient: Client[IO] = JavaNetClientBuilder[IO](blocker).create
val uriYandex = uri"https://ya.ru"

val lstHeader: List[Header] =List(
  Header("Accept","text/plain")
  ,Header("Accept-Charset","utf-8")
  ,Header("Accept-Encoding","*")
)

val request2 = Request[IO](Method.GET, uriYandex, HttpVersion.`HTTP/2.0`, Headers(lstHeader))
val httpReq = httpClient.expect[String](request2)
val app = httpReq.map(resString => resString)

app.unsafeRunSync

如果我在IDEA Scala工作表中运行http4s版本"0.21.3“。它工作良好，输出如下：

res0: class==

res0: String =？p?320？，Y？？+d?9？&6&66 F?3？？{？？7？

我试过不同的译码器，但有了这个错误：

失败(java.util.zip.ZipException:不采用GZIP格式)

Answer 1

您不能只发送Accept-Encoding头，因为当您执行httpClient.expect[String]时，HTTP将尝试将数据解码为一个字符串，并且它不知道它需要首先解压缩数据。

尝试使用GZip中间件。

Answer 2

谢谢大家。我解决了下一次使用GZip的问题。

import org.http4s.client.middleware.GZip
val gzClient = GZip()(httpClient)
val httpReq = gzClient.expect[String](request2)
val app = httpReq.map(resString => resString)