下面的查询只需要很长的时间,下面的谓词只用于获取唯一的记录,因此想知道是否有不同的方法可以重写相同的查询而不多次调用下面的谓词,以获得唯一的ID。
select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)
select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)
select max(pr.id) from patentpr where pr.ids = p.ids and pr.idc = p.idc) 我的完整示例查询
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM patent p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN plocation y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.id = *(select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)*
AND y.idopstype in (36, 37)
JOIN plocation_log yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.id = *(select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)*
AND yt.idopstype in (36,37)
WHERE
p.idp IN (10,20,30)
AND p.id = *(select max(pr.id) from patent pr where pr.ids = p.ids and pr.idc = p.idc)*
AND p.idopstype in (36,37)发布于 2020-07-31 18:22:44
考虑加入聚合MAX,以计算每组的值一次,而不是对每个外部查询行按行进行MAX计算。此外,请确保使用更多信息丰富的表别名,而不是使用a, b, c或x, y, z样式。
WITH loc_max AS
(select ids, idc, max(id) as max_id from plocation group ids, idc)
, log_max AS
(select ids, idc, max(id) as max_id from plocation_log group by ids, idc)
, pat_max AS
(select ids, idc, max(id) as max_id from patent pr group by ids, idc)
SELECT to_char(pat.pid) AS patentid
, pat.name
, det.dept
, loc.location
FROM patent pat
JOIN pdetails det
ON pat.pid = det.pid
AND det.isactive = 1
JOIN plocation loc
ON loc.idr = pat.idr
AND loc.idc = pat.idc
AND loc.idopstype IN (36, 37)
JOIN loc_max -- ADDED CTE JOIN
ON loc.id = loc_max.max_id
AND loc.ids = loc_max.ids
AND loc.idc = loc_max.idc
JOIN plocation_log log
ON log.idr = log.idr
AND log.idc = log.idc
AND log.idopstype in (36,37)
JOIN log_max -- ADDED CTE JOIN
ON log.id = log_max.max_id
AND log.ids = log_max.ids
AND log.idc = log_max.idc
JOIN pat_max -- ADDED CTE JOIN
ON pat.id = pat_max.max_id
AND pat.ids = pat_max.ids
AND pat.idc = pat_max.idc
WHERE pat.idp IN (10, 20, 30)
AND pat.idopstype IN (36, 37)发布于 2020-07-31 17:03:24
正如Impaler所评论的,一种选择是使用分析函数而不是相关的子查询。其思想是使用RANK()对子查询中的记录进行排序,然后在外部查询中筛选(联接条件或WHERE子句)。
考虑:
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM (SELECT p.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM patinet) p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation y) y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.idopstype in (36, 37)
AND y.rn = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation_log yt) yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.idopstype in (36,37)
AND yt.rn = 1
WHERE
p.idp IN (10,20,30)
AND p.idopstype in (36,37)
AND p.rn = 1https://stackoverflow.com/questions/63195480
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