我有以下自定义用户模型的代码。谁能帮我解决我的,一个解决方案,以限制超级用户访问管理网站,只有。提前感谢
# UserManager is for Custom User Model to override Django's Default Model
class UserManager(BaseUserManager):
def _create_user(self, email, password, is_superuser, **extra_fields):
if not email or not password:
raise ValueError("The given username or password must not be null")
user = self.model(
email=email,
password=password,
is_superuser=is_superuser,
last_login=now,
**extra_fields
)
user.set_password(password)
user.save(using=self._db)
return user
def create_user(self, email, password=None, **extra_fields):
return self._create_user(email, password, False, **extra_fields)
def create_superuser(self, email, password=None, **extra_fields):
return self._create_user(email, password, True, **extra_fields)
class Users(AbstractBaseUser):
email = models.EmailField(max_length=255, unique=True)
is_active = models.BooleanField(default=True)
is_admin = models.BooleanField(default=False)
is_superuser = models.BooleanField(default=False)
created_at_utc = models.DateTimeField(auto_now_add=True)
objects = UserManager()
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = ['password']
def __str__(self):
return self.email
def has_perm(self, perm, obj=None):
"Does the user have a specific permission?"
# Simplest possible answer: Yes, always
return True
def has_module_perms(self, app_label):
"Does the user have permissions to view the app `app_label`?"
# Simplest possible answer: Yes, always
return self.is_admin
def is_staff(self):
"Is the user a member of staff?"
# Simplest possible answer: All admins are staff
return self.is_admin
class Meta:
db_table = "users"我有上面的代码为用户,下面的代码为管理面板创建和更新用户的谁可以帮助我用一个解决方案,以限制超级用户访问管理网站仅。提前感谢
class UserCreateForm(UserCreationForm):
class Meta:
model = Users
fields = (
"email","is_admin","is_superuser",
)
class UserChangeForm(BaseUserChangeForm):
class Meta:
model = Users
fields = (
"email","is_admin",
)
class UserAdmin(BaseAdmin):
form = UserChangeForm
add_form = UserCreateForm
fieldsets = (
(None, {"fields": ("email", "password","is_active","is_admin","is_superuser")}),
)
add_fieldsets = (
(None, {
"classes": ("wide",),
"fields": ("email", "password1", "password2","is_active","is_admin","is_superuser")}
),
)
filter_horizontal = ()
list_display = ("email","is_active", )
list_filter = ("is_active", )
search_fields = ("email",)
ordering = ("email",)
# Register your models here.
admin.site.register(Users, UserAdmin)我尝试过许多解决方案,以限制超级用户访问管理员页面时,登录细节是提供的。谁能帮我解决我的解决方案,以限制超级用户访问管理网站仅。提前感谢
发布于 2020-08-05 10:05:37
我认为您正在寻找的字段是is_staff,它位于
class AbstractUser(AbstractBaseUser, PermissionsMixin):
您可以从
from django.contrib.auth.models import AbstractUser
您会发现它有一个名为is_staff的字段,所以这基本上是布尔字段,它决定用户是否有登录管理站点的权限,以获得更多的信息,可以进行google搜索或找到下面的文章。
https://www.webforefront.com/django/adminpermissions.html
我看到您已经将函数创建为def is_staff(self):但是您没有使用字段is_staff
发布于 2021-10-03 11:21:50
也有同样的问题。而不是password=None,而是将其改为password。并将password=password与username=username一起传递到create_user函数中,如下所示
class MyAccountManager(BaseUserManager):
def create_user(self, email, username, password):
if not email:
raise ValueError('Please add an email address')
if not username:
raise ValueError('Please add an username')
user = self.model(email=self.normalize_email(
email), username=username, password=password)
user.set_password(password)
user.save(using=self._db)
return user
def create_superuser(self, email, username, password):
user = self.create_user(email=self.normalize_email(
email), username=username, password=password)
user.is_active = True
user.is_admin = True
user.is_staff = True
user.is_superuser = True
user.save(using=self._db)
return user希望它对你有用
https://stackoverflow.com/questions/63261120
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