我正在尝试在.UnionAll库中使用围棋方法。
var model []Customer
q0 := db.Model(&model).Where("name = ?", name0).Limit(4)
q1 := db.Model(&model).Where("name = ?", name1).Limit(3)
var result []Customer
if err := q0.UnionAll(q1).Limit(1).Select(&result); !as.NoError(err) {
return
}此代码生成查询:
(SELECT "customer"."id", "customer"."name" FROM customers AS "customer" WHERE (name = 'customer 1deificatory zonoid reprepare alacrify serenissime')
LIMIT 1)
UNION ALL
(SELECT "customer"."id", "customer"."name" FROM customers AS "customer" WHERE (name = 'customer 2fordless ferroboron radiability dandizette smutch'
LIMIT 3)
)但我希望它是:
(SELECT "customer"."id", "customer"."name" FROM customers AS "customer" WHERE (name = 'customer 1deificatory zonoid reprepare alacrify serenissime')
LIMIT 4)
UNION ALL
(SELECT "customer"."id", "customer"."name" FROM customers AS "customer" WHERE (name = 'customer 2fordless ferroboron radiability dandizette smutch')
LIMIT 3)
LIMIT 1那么,如何使用go来获取我所期望的原始SQL查询呢?问题是,由于某些原因,我无法将Limit 1表达式应用于整个查询。另外,我的Limit 4没有正确地应用于第一个union all成员。我的全部代码是这里。
发布于 2020-08-09 13:41:18
我相信这个查询对你有好处。
if err := db.Model().With("union_q", q0.UnionAll(q1)).Table("union_q").Limit(1).Select(&result); !as.NoError(err) {
return
}这个查询不是您想要的,据我所知,当前版本的go无法生成该查询。但这个查询完全符合您的要求。
https://stackoverflow.com/questions/63277841
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