UnrecognizedPropertyException in FasterXML

Question

当我使用"{"name":"John","timestamp":"2020-08-14T11:47:52.297194Z"}"将字符串fasterXML转换为POJO时，我会看到以下异常，

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "timestamp" (class com.job.model.Person), not marked as ignorable (2 known properties:  "name", "timeStamp"])

我的波乔是，

@Data
@NoArgsConstructor
@Table(keyspace = "keyspace", name = "testTable")
public class Person implements Serializable {

    private static final long serialVersionUID = 1L;

  
    @Column(name = "name")
    private String name;


    @Column(name = "timeStamp")
    //@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss", timezone = "UTC") // Tried with this no luck.
    private Instant timeStamp; 

}

我从下面的url中添加了所需的依赖项，

https://github.com/FasterXML/jackson-modules-java8，以及

 <dependency>
           <groupId>com.fasterxml.jackson.core</groupId>
           <artifactId>jackson-databind</artifactId>
           <version>2.11.0</version>
       </dependency>

ObjectMapper objectMapper = JsonMapper.builder()
            .addModule(new ParameterNamesModule())
            .addModule(new Jdk8Module())
            .addModule(new JavaTimeModule())
            .build();

都是注册的。

Answer 1

Json拥有timestamp，而pojo拥有timeStamp。要么在pojo中重命名，要么使用@JsonProperty("timestamp")

@JsonProperty("timestamp")
private Instant timeStamp;