我正在Arduino UNO上编程,遇到了一个非常烦人的路障。
我对PROGMEM有一个很奇怪的问题,我把它缩小到了一个指针数组的问题上。
当我用变量j索引PROGMEM数组时,它根据天气返回不同的结果,变量j是由一个静态数字设置的,或者是由另一个变量设置的。
程序号是存储在对象中的整数,并且只按以下方式设置,内存被调出,变量保存其值。我已经测试过了。
*(this->program) = 0;将j设为0直接生成正确的地址。
uint16_t j = 0;
Serial.println(j);
//printed 0 as expected
address = (uint16_t)*(pgmStringTable + (uint16_t)j);
Serial.println(address);
//gave address = 105, which is correct and PROGMEM reads the correct bytes但是,使用下列方案变量设置j会产生不正确的地址
uint16_t j = *(this->program);
Serial.println(j);
//printed 0 as expected
address = (uint16_t)*(pgmStringTable + (uint16_t)j);
Serial.println(address);
//gave address = 4, which isnt right and results in PROGMEM read errors即使试图解决这个集合问题,比如在*(这个->程序)上做一些算术运算,或者把它发送给一个返回相同值的整数的函数,都于事无补。唯一有作用的是循环遍历所有整数,如下所示:
//loops through most unsigned integer values
for(uint16_t j = 0; j < 65000; j++){
if(j == *(this->program)){
address = (uint16_t)*(pgmStringTable + (uint16_t)j);
//address is correct and PROGMEM works correctly
}
}以上工作更有理由确认malloc是否正确工作,因为*(此->程序)在将malloc与j进行比较时返回正确的值。
这是一个非常糟糕的工作,因为它的效率非常低,将导致主要的周期浪费在我的程序,这是相当的时间敏感。
任何指向解决方案的指针或指针行为滑稽的原因都是非常有用的。
这个问题来自一个非常大的项目,因此为了帮助缩小错误,我在一个小得多的.ino文件中重新创建了这个问题。
整个代码是这样的。它在上传我的arduino UNO时也会产生同样的错误。
编辑:
const char pgmString1[] PROGMEM = "String 1__";
const char pgmString2[] PROGMEM = "2nd String";
const char *const pgmStringTable[] PROGMEM = {pgmString1, pgmString2};
class testObject{
private:
uint16_t* program;
public:
testObject(){
program = (uint16_t*) malloc(sizeof(uint16_t));
*(this->program) = 0;
}
void read(){
if(*(this->program) == 0){
//the console prints the below, meaning the value is definitly 0
Serial.println("it was 0");
*(this->program) = 0;
}else{
Serial.println("it wasnt 0");
//if this is uncommeneted, this program outputs the correct values but the above comment will not be dispalyed
//*(this->program) = 0;
}
char temp[10];
uint16_t j = 0;
uint16_t address = 0;
////////////////////////////////////////////// indirectly setting j
//sets the j value to be 0, which is what is stored in this->program
j = *(this->program);
//prints j to make sure its 0, then finds the address of the progmem string
Serial.print(j);
Serial.print(" 1 Address: |");
address = (uint16_t)*(pgmStringTable + (uint16_t)j);
Serial.print(address); //the address printed is incorrect
Serial.print(" ");
//reads byte by byte from the address, it reads the wrong bytes
for(int i = 0; i < 10; i++){
char myChar = pgm_read_byte( address + i );
Serial.print(myChar);
}
Serial.println("\n");
////////////////////////////////////////////// directly setting j
//but just setting j = 0 works fine
j=0;
//so directly setting j as 0, same code as above but it produces the correct output
//SAME AS ABOVE, COULDNT SEPERATE INTO ITS ONW FUNCTION
Serial.print(j);
Serial.print(" 2 Address: |");
address = (uint16_t)*(pgmStringTable + (uint16_t)j);
Serial.print(address);
Serial.print(" ");
for(int i = 0; i < 10; i++){
char myChar = pgm_read_byte( address + i );
Serial.print(myChar);
}
Serial.println();
//
}
};
testObject pgmReader;
void setup(){
Serial.begin(9600);
}
void loop(){
Serial.println("\n\n\n\n\n\n\n\n");
delay(1000);
pgmReader.read();
}发布于 2020-08-17 14:04:45
不仅pgmString1和pgmString2,pgmStringTable也是PROGMEM。因此,您必须使用pgm_read_函数从pgmStringTable中读取。
address = pgm_read_ptr(pgmStringTable + (uint16_t)j);https://stackoverflow.com/questions/63447172
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