有人能解释一下如何实现聊天日志的新行处理程序修复吗？

Question

我真的不知道如何在标题中解释这一点。问题是，我查找文本通道中的所有消息并将其填充到列表中，然后将其保存到文本文件中。由于在聊天客户端中形成，消息的内容具有新行。聊天记录器只保存带有换行符的所有消息，从而损害日志文件。

聊天客户端输入

user1: who are the users on this server?
user2: oh that' easy my name is harry
       user3 is adam
       user4 is max
user1: okay got that

中断聊天记录器输出

12345 user1: who are the users on this server?
23456 user2: oh that' easy my name is harry
user3 is adam
user4 is max
12345 user1: okay got that

我想要实现的

12345 user1: who are the users on this server?
23456 user2: oh that' easy my name is harry
23456 user2: user3 is adam
23456 user2: user4 is max
12345 user1: okay got that

或

12345 user1: who are the users on this server?
23456 user2: oh that' easy my name is harry user3 is adam user4 is max
12345 user1: okay got that

有什么窍门可以实现吗？我可以做string.replace('\n'，‘')，但是我对我建议的第一个方法更感兴趣。

Answer 1

第三个选项如何，使用日志中字符串的repr版本：

messages = [
    (12345, 'user1: who are the users on this server?'),
    (23456, '''user2: oh that' easy my name is harry
user3 is adam
user4 is max'''),
    (12345, 'user1: okay got that'),
    ]

for x, msg in messages:
    print(x, repr(msg))

输出：

12345 'user1: who are the users on this server?'
23456 "user2: oh that' easy my name is harry\nuser3 is adam\nuser4 is max"
12345 'user1: okay got that'

这样您就不必实现像第一个示例输出那样的特殊格式，也不必丢失像第二个示例输出中的信息(将换行符压缩到空格中)。