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Question

我需要遍历一个对象，并访问它的属性，使用存档查找数组。我想检查密钥的属性是否是instanceof和Array。请考虑以下几点：

const record: MainRecord = {
  id: "10",
  fieldOne: "Foo",
  __typename: "Main",
  related: [
    {
      id: "20",
      fieldTwo: "Bar",
      __typename: "Related"
    },
    {
      id: "21",
      fieldTwo: "Baz",
      __typename: "Related"
    },
  ]
}

// Want to iterate over the keys and check for Array type values
// regardless of what the name of the property is.
_.keys(record).map((key) => {
  console.log(key);

  record["related"] instanceof Array   // No TS compiler error.
  record["id"] instanceof Array        // TS compiler error!
  record["id"] as any instanceof Array // This is actually fine apparently.
  record[key] instanceof Array         // Error! (this is what I'm trying to do)
  record[key] as any instanceof Array  // ALSO an error. Why is this?

  // if(record[key] instanceof Array) {
  //   // ....
  // }      
})

当我尝试检查instanceof record[key]时，会得到以下编译器错误：

Element implicitly has an 'any' type because expression of type 'string' can't be used to index type 'MainRecord'. No index signature with a parameter of type 'string' was found on type 'MainRecord'.

有什么想法吗？

Answer 1

TypeScript编译器在record[key]中抱怨key的类型是string而不是keyof MainRecord，这可能是因为key keys()方法的类型不精确，可能和Object.keys()的类型一样多。

您应该使用类型断言来解决这个问题：

_.keys(record).map(k => {
  const key = k as keyof MainRecord;
  // if (record[key] instanceof Array) {
  //   // ....
  // }      
})