let arr = [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5)]
arr.map(\.0) // [1, 2, 3, 4, 5]效果很好。但是下面的代码没有编译:
let keyPath = \(Int, Int).0
arr.map(keyPath)无法将'WritableKeyPath<(Int,Int),Int>‘类型的值转换为预期的参数类型((Int,Int))引发-> T’。 无法推断泛型参数'T‘。
发布于 2020-09-06 15:24:12
进化论建议展示了如何使用操作符,但您也可以使用相同的[]或()语法,不管它是否部分应用,因为下标和函数不需要参数。
let oneTo5 = 1...5
let keyPath = \(Int, Int).0
XCTAssert(
zip(oneTo5, oneTo5).map(keyPath[]).elementsEqual(oneTo5)
)let keyPath = \Double.isZero
XCTAssertFalse(keyPath[1.0]())public extension KeyPath {
/// Convert a `KeyPath` to a partially-applied get accessor.
subscript() -> (Root) -> Value {
{ $0[keyPath: self] }
}
/// Convert a `KeyPath` to a get accessor.
subscript(root: Root) -> () -> Value {
{ root[keyPath: self] }
}
}
public extension ReferenceWritableKeyPath {
/// Convert a `KeyPath` to a partially-applied get/set accessor pair.
subscript() -> (Root) -> Computed<Value> {
{ self[$0] }
}
/// Convert a `KeyPath` to a get/set accessor pair.
subscript(root: Root) -> Computed<Value> {
.init(
get: self[root],
set: { root[keyPath: self] = $0 }
)
}
}/// A workaround for limitations of Swift's computed properties.
///
/// Limitations of Swift's computed property accessors:
/// 1. They are not mutable.
/// 2. They cannot be referenced as closures.
@propertyWrapper public struct Computed<Value> {
public typealias Get = () -> Value
public typealias Set = (Value) -> Void
public init(
get: @escaping Get,
set: @escaping Set
) {
self.get = get
self.set = set
}
public var get: Get
public var set: Set
public var wrappedValue: Value {
get { get() }
set { set(newValue) }
}
public var projectedValue: Self {
get { self }
set { self = newValue }
}
}
//MARK:- public
public extension Computed {
init(
wrappedValue: Value,
get: @escaping Get = {
fatalError("`get` must be assigned before accessing `wrappedValue`.")
},
set: @escaping Set
) {
self.init(get: get, set: set)
self.wrappedValue = wrappedValue
}
}https://stackoverflow.com/questions/63764608
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