我需要用一个映射序列化一个类,以便在json中对映射中的键进行排序。所以如果有一个类
@Serializable
class Example(val map: Map<String, Int>)并且它被序列化为
val example = Example(mapOf("b" to 2, "a" to 1, "c" to 3))
println(Json.encodeToString(example))那么产生的json应该是
{
"map": {
"a": 1,
"b": 2,
"c": 3
}
}我试图使用SortedMap而不是Map,但这引发了一个异常:
kotlinx.serialization.SerializationException:类“TreeMap”未在“SortedMap”范围内注册多态序列化
如何使用kotlinx.serialization获得排序的json
(kotlin 1.4.0,kotlinx.serialization 1.0.0-RC)
发布于 2020-09-16 09:14:26
弄明白了:
import kotlinx.serialization.*
import kotlinx.serialization.json.*
import kotlinx.serialization.builtins.*
import kotlinx.serialization.descriptors.SerialDescriptor
import kotlinx.serialization.encoding.Decoder
import kotlinx.serialization.encoding.Encoder
object SortedMapSerializer: KSerializer<Map<String, Int>> {
private val mapSerializer = MapSerializer(String.serializer(), Int.serializer())
override val descriptor: SerialDescriptor = mapSerializer.descriptor
override fun serialize(encoder: Encoder, value: Map<String, Int>) {
mapSerializer.serialize(encoder, value.toSortedMap())
}
override fun deserialize(decoder: Decoder): Map<String, Int> {
return mapSerializer.deserialize(decoder)
}
}
@Serializable
class Example(
@Serializable(with = SortedMapSerializer::class)
val map: Map<String, Int>
)
fun main() {
val example = Example(mapOf("b" to 2, "c" to 3, "a" to 1))
println(Json.encodeToString(
example
))
}(虽然有一个Map<Serializable, Serializable>的答案会很好
https://stackoverflow.com/questions/63904357
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