在plt.imshow()中将alpha设置为数组会使绘图崩溃

Question

当试图运行这段受matplotlib文档启发的小代码时，二维图像的透明性与颜色的融合

import numpy as np
import matplotlib.pyplot as plt

test = np.random.random((300, 300))

plt.figure()
plt.imshow(test, alpha = test/test.max())
plt.show()

最后，我：

<matplotlib.image.AxesImage at 0x7f8bfe8cc610>Traceback (most recent call last):
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/backends/backend_qt5.py", line 508, in _draw_idle
    self.draw()
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/backends/backend_agg.py", line 388, in draw
    self.figure.draw(self.renderer)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/artist.py", line 38, in draw_wrapper
    return draw(artist, renderer, *args, **kwargs)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/figure.py", line 1709, in draw
    renderer, self, artists, self.suppressComposite)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/image.py", line 135, in _draw_list_compositing_images
    a.draw(renderer)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/artist.py", line 38, in draw_wrapper
    return draw(artist, renderer, *args, **kwargs)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/axes/_base.py", line 2647, in draw
    mimage._draw_list_compositing_images(renderer, self, artists)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/image.py", line 135, in _draw_list_compositing_images
    a.draw(renderer)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/artist.py", line 38, in draw_wrapper
    return draw(artist, renderer, *args, **kwargs)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/image.py", line 619, in draw
    renderer, renderer.get_image_magnification())
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/image.py", line 881, in make_image
    unsampled=unsampled)
  File "/Users/darkvador/opt/anaconda3/lib/python3.7/site-packages/matplotlib/image.py", line 530, in _make_image
    np.asarray(alpha_channel, np.float32) * out_alpha * alpha,
ValueError: operands could not be broadcast together with shapes (740,740) (300,300)

我在macos-catalina下面，和python：

Python 3.7.7 (default, Mar 26 2020, 10:32:53) 
[Clang 4.0.1 (tags/RELEASE_401/final)] :: Anaconda, Inc. on darwin 

请注意，在下列情况下不会发生错误：

• 我评论plt.show()
• 我使用常量alpha-value
• 我在linux发行版的经典python3.6下运行了这段代码

Answer 1

在matplotlib 3.1.3文档中，alpha关键字参数必须是标量值。

您应该更新到Matplotlib 3.3.1，因为为alpha参数提供数组必须是在这两个版本之间实现的。

Answer 2

您的alpha数组alpha/alpha.max()与实际图像数组test的形状不匹配。从您提供的测试代码中，我们可以创建一个alpha数组，并成功地将其显示为以下代码的α变化图像。因此，您必须确保alpha数组具有与test数组完全相同的形状。

import numpy as np
import matplotlib.pyplot as plt

test = np.random.random((300, 300))
alpha = test / test.max()
print(alpha)

plt.figure()
plt.imshow(test, alpha = alpha)
plt.show()

产生下面的图像。

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