我试图构建并举例了解DI框架/库是如何工作的,但我遇到了一些问题。
我有两个可能实现的接口:
export interface Operation {
calculate(a: number, b: number): number;
}sub.ts
import { Operation } from "./operation.interface";
export class Sub implements Operation {
calculate(a: number, b: number): number {
return Math.abs(a - b);
}
}sum.ts
import { Operation } from "./operation.interface";
export class Sum implements Operation {
calculate(a: number, b: number): number {
return a + b;
}
}calculator.ts
import { Operation } from "./operation.interface";
import {injectable, inject} from "tsyringe";
@injectable()
export class Calculator {
constructor(@inject("Operation") private operation?: Operation){}
operate(a: number, b: number): number {
return this.operation.calculate(a, b);
}
}index.ts
import "reflect-metadata";
import { container } from "tsyringe";
import { Calculator } from "./classes/calculator";
import { Sub } from "./classes/sub";
import { Sum } from "./classes/sum";
container.register("Operation", {
useClass: Sum
});
container.register("OperationSub", {
useClass: Sub
});
const calculatorSum = container.resolve(Calculator);
const result = calculatorSum.operate(4,6);
console.log(result);
// const calculatorSub = ???有什么办法可以让我有两个不同行为的计算器,还是我做错了?
发布于 2020-10-13 11:59:05
因为OperationSub不在任何地方使用,所以它不会影响注入的Operation值。
不同依赖集的计算器应该用多容器表示。求和计算器可以被视为默认实现并使用根容器,或者这两个实现都可以由子容器表示,而根容器仍然是抽象的。
// common deps are registered on `container`
const sumContainer = container.createChildContainer();
const subContainer = container.createChildContainer();
sumContainer.register("Operation", { useClass: Sum });
subContainer.register("Operation", { useClass: Sub });
const calculatorSum = sumContainer.resolve(Calculator);
const calculatorSub = subContainer.resolve(Calculator);https://stackoverflow.com/questions/64334425
复制相似问题