关于如何从UIDAI Aadhaar卡的安全QR代码读取QR代码数据的正式文档:15032019.pdf
使用zxing扫描器扫描安全的QR代码,并在Github:https://github.com/dimagi/AadharUID中的以下项目的帮助下获得了aadhar卡的详细信息。
如何利用文档上的说明从转换后的字节数组中提取照片和bit_indicator_value
但是,我无法从Aadhar卡字节数组的安全QR代码中获得电子邮件和移动的精确哈希值来验证。
我对第6页上述文件的这一行感到有点困惑:
我还准备了第6页文档中的最后一步,但是用户移动/电子邮件哈希值和文档移动/电子邮件字节数组哈希值永远不匹配。
代码片段:
public ScanResult(String input) {
rawString = input;
// copied from http://www.java-samples.com/showtutorial.php?tutorialid=152
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
Document dom;
try {
//Using factory get an instance of document builder
DocumentBuilder db = dbf.newDocumentBuilder();
// Replace </?xml... with <?xml...
if (input.startsWith("</?")) {
input = input.replaceFirst("</\\?", "<?");
}
// Replace <?xml...?"> with <?xml..."?>
input = input.replaceFirst("^<\\?xml ([^>]+)\\?\">", "<?xml $1\"?>");
//parse using builder to get DOM representation of the XML file
dom = db.parse(new ByteArrayInputStream(input.getBytes("UTF-8")));
} catch (ParserConfigurationException | SAXException | IOException e) {
dom = null;
}
if (rawString.matches("[0-9]*")) {
type = QR_CODE_TYPE_SECURE;
byte[] msgInBytes = null;
try {
msgInBytes = decompressByteArray(new BigInteger(rawString).toByteArray());
} catch (IOException e) {
e.printStackTrace();
}
if (msgInBytes != null) {
int[] delimiters = locateDelimiters(msgInBytes);
String referenceId = getValueInRange(msgInBytes, delimiters[0] + 1, delimiters[1]);
uid = referenceId.substring(0, 4);
name = getValueInRange(msgInBytes, delimiters[1] + 1, delimiters[2]);
dob = formatDate(getValueInRange(msgInBytes, delimiters[2] + 1, delimiters[3]),
new String[] {"dd-MM-yyyy", "dd/MM/yyyy"});
yob = dob.substring(0, 4);
gender = getValueInRange(msgInBytes, delimiters[3] + 1, delimiters[4]);
co = getValueInRange(msgInBytes, delimiters[4] + 1, delimiters[5]);
dist = getValueInRange(msgInBytes, delimiters[5] + 1, delimiters[6]);
lm = getValueInRange(msgInBytes, delimiters[6] + 1, delimiters[7]);
house = getValueInRange(msgInBytes, delimiters[7] + 1, delimiters[8]);
loc = getValueInRange(msgInBytes, delimiters[8] + 1, delimiters[9]);
pc = getValueInRange(msgInBytes, delimiters[9] + 1, delimiters[10]);
po = getValueInRange(msgInBytes, delimiters[10] + 1, delimiters[11]);
state = getValueInRange(msgInBytes, delimiters[11] + 1, delimiters[12]);
street = getValueInRange(msgInBytes, delimiters[12] + 1, delimiters[13]);
subdist = getValueInRange(msgInBytes, delimiters[13] + 1, delimiters[14]);
vtc = getValueInRange(msgInBytes, delimiters[14] + 1, delimiters[15]);
statusCode = STATUS_SUCCESS;
} else {
statusCode = STATUS_PARSE_ERROR;
uid = "";
name = "";
gender = "";
yob = "";
co = "";
house = "";
street = "";
lm = "";
loc = "";
vtc = "";
po = "";
dist = "";
subdist = "";
state = "";
pc = "";
dob = "";
}
} else {
type = QR_CODE_TYPE_UNKNOWN;
statusCode = STATUS_PARSE_ERROR;
uid = "";
name = "";
gender = "";
yob = "";
co = "";
house = "";
street = "";
lm = "";
loc = "";
vtc = "";
po = "";
dist = "";
subdist = "";
state = "";
pc = "";
dob = "";
}
dobGuess = getDobGuess(dob, yob);
statusText = getStatusText(statusCode);
}
private static int[] locateDelimiters(byte[] msgInBytes) {
int[] delimiters = new int[NUMBER_OF_PARAMS_IN_SECURE_QR_CODE + 1];
int index = 0;
int delimiterIndex;
for (int i = 0; i <= NUMBER_OF_PARAMS_IN_SECURE_QR_CODE; i++) {
delimiterIndex = getNextDelimiterIndex(msgInBytes, index);
delimiters[i] = delimiterIndex;
index = delimiterIndex + 1;
}
return delimiters;
}
private static String getValueInRange(byte[] msgInBytes, int start, int end) {
return new String(Arrays.copyOfRange(msgInBytes, start, end), Charset.forName("ISO-8859-1"));
}
private static int getNextDelimiterIndex(byte[] msgInBytes, int index) {
int i = index;
for (; i < msgInBytes.length; i++) {
if (msgInBytes[i] == -1) {
break;
}
}
return i;
}
private static byte[] decompressByteArray(byte[] bytes) throws IOException {
java.io.ByteArrayInputStream bytein = new ByteArrayInputStream(bytes);
java.util.zip.GZIPInputStream gzin = new GZIPInputStream(bytein);
java.io.ByteArrayOutputStream byteout = new ByteArrayOutputStream();
int res = 0;
byte buf[] = new byte[1024];
while (res >= 0) {
res = gzin.read(buf, 0, buf.length);
if (res > 0) {
byteout.write(buf, 0, res);
}
}
return byteout.toByteArray();
}
private String formatDate(String rawDateString, String[] possibleFormats) {
if (rawDateString.equals("")) {
return "";
}
SimpleDateFormat toFormat = new SimpleDateFormat("yyyy-MM-dd");
Date date = null;
ParseException parseException = null;
for (String fromFormatPattern : possibleFormats) {
try {
SimpleDateFormat fromFormat = new SimpleDateFormat(fromFormatPattern);
date = fromFormat.parse(rawDateString);
break;
} catch (ParseException e) {
parseException = e;
}
}
if (date != null) {
return toFormat.format(date);
} else if (parseException != null) {
System.err.println("Expected dob to be in dd/mm/yyyy or yyyy-mm-dd format, got " + rawDateString);
return rawDateString;
} else {
throw new AssertionError("This code is unreachable");
}
}
@NonNull
protected String formatGender(String gender) throws ParseException {
String lowercaseGender = gender.toLowerCase();
if (lowercaseGender.equals("male") || lowercaseGender.equals("m")) {
return "M";
} else if (lowercaseGender.equals("female") || lowercaseGender.equals("f")) {
return "F";
} else if (lowercaseGender.equals("other") || lowercaseGender.equals("o")) {
return "O";
} else {
throw new ParseException("404 gender not found", 0);
}
}
@NonNull
private String getStatusText(int statusCode) {
switch (statusCode) {
case ScanResult.STATUS_SUCCESS:
return "✓";
default:
return "✗";
}
}
@NonNull
private String getDobGuess(String dob, String yob) {
if (dob.equals("")) {
Integer yearInt;
try {
yearInt = Integer.parseInt(yob);
} catch (NumberFormatException e) {
return "";
}
// June 1 of the year
return Integer.toString(yearInt) + "-06-01";
} else {
return dob;
}
}发布于 2020-10-14 06:25:08
刚刚得到了解决方案,从字节数组中获取精确的移动和电子邮件哈希值。
首先从字节数组中删除最后256个字节,
如果只有移动的存在,那么从移动字节数组中取出最后的32个字节,即(array.length - 32到array.length)
否则,如果仅存在电子邮件,则从字节数组获取电子邮件的最后32个字节,即(array.length - 32到array.length)。
否则,如果电子邮件和移动通信都来自移动字节数组的最后32个字节,则取后32个字节作为电子邮件,即( array.length - 32 to array.length,email = array.length - 64 to array.length - 32)。
发布于 2021-06-08 16:19:37
从字节数组中,您需要从索引byte_array_length - 256 - 32读取值到byte_array_length - 256,以获得以字节为单位的移动散列(您可以轻松地将字节转换为十六进制字符串),同样,对于电子邮件,您需要从索引byte_array_length - 256 - 32 - 32读取到byte_array_length - 256 - 32。
我已经实现了一个用于解码的库,但是实现是用Python实现的。
这个问题有点老了,但未来的读者可能会发现这些资源很有用。
PyPI:阿达尔-比
https://stackoverflow.com/questions/64341259
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