Numba namedtuple签名

Question

我正在尝试为Numba中的namedtuple指定返回类型，但我无法这样做。有人能帮忙吗？考虑以下最起码的代码：

import numba as nb
from   collections import namedtuple

NT = namedtuple('NT',['sum','sum2'])

@nb.njit((nb.types.NamedTuple([nb.float64,nb.float64],NT))(nb.int64,nb.float64[:,:]),fastmath=True)
def arrsum_njit(nn,xx):
    arraysum = 0.0
    out = NT(sum=arraysum,sum2=arraysum)
    return out

我知道错误了

No conversion from NT(float64 x 2) to NT(float64, float64) for '$20return_value.7', defined at None

File "numbanamedtuple.py", line 10:
def arrsum_njit(nn,xx):
    <source elided>
    out = NT(sum=arraysum,sum2=arraysum)
    return out
    ^

During: typing of assignment at numbanamedtuple.py (10)

File "numbanamedtuple.py", line 10:
def arrsum_njit(nn,xx):
    <source elided>
    out = NT(sum=arraysum,sum2=arraysum)
    return out

Answer 1

问题是“过度优化”numba编译器(bug)。向元组中添加不同类型的变量，以告诉编译器使用异构元组(内部类)。

import numba as nb
from   collections import namedtuple

NT = namedtuple('NT',['sum','sum2','dummy'])

@nb.njit((nb.types.NamedTuple([nb.float64,nb.float64,nb.int64],NT))(nb.int64,nb.float64[:,:]),fastmath=True)
def arrsum_njit(nn,xx):
    arraysum = 0.0
    out = NT(sum=arraysum,sum2=arraysum,dummy=1)
    return out

Upd:测试：

• Numba 0.51.2/ Windows
• Numba 0.48.0/ Google LinuxUbuntu18.04.5 LTS

Answer 2

使用NamedUniTuple代替。它是同质名词元组的numba规范类型。