将SMTP Sendgrid转换为Sendgrid API

Question

目前，将旧的SMTP Sendgrid替换为and，我注意到它们的code.But有一些不同，我认为既然它们都是Sendgrid，它就能工作。我所做的是在最后添加这个SendGridClient.SendEmailAsync(Message);。但上面写着

不能从system.net.mail.mailmessage转换为sendgrid.helpers.mail.sendgridmessage

这是正确的转换方式吗？

下面是密码。

        try
        {
            string SendGridKey = ConfigurationManager.AppSettings["SendGridKey"];
            var SendGridClient = new SendGridClient(SendGridKey);
            using (MailMessage MessageContent = new MailMessage())
            {
                MessageContent.From = new MailAddress(From);
                MessageContent.To.Add(new MailAddress(To));
                MessageContent.Subject = Subject;
                MessageContent.Body = (TextBody);
                ContentType mimeType = new System.Net.Mime.ContentType("text/html");
                AlternateView Alternate = AlternateView.CreateAlternateViewFromString(HtmlBody, mimeType);
                Message.AlternateViews.Add(Alternate);
                if (AttachedFileName == true)
                {
                    Attachment AttachedFile = new Attachment(HttpRuntime.AppDomainAppPath + "Path\\" + AttachedFileName);
                    MessageContent.Attachments.Add(AttachedFile);
                }

                //using (SmtpClient Client = new SmtpClient())
                //{
                //    Client.EnableSsl = true;
                //    Client.Send(MessageContent);
                //}
                  SendGridClient.SendEmailAsync(Message);
            }
            return;
        }

Answer 1

要使用SendGrid API发送邮件，需要创建com.sendgrid.Request对象。为java添加代码：

import com.sendgrid.Content;
import com.sendgrid.Email;
import com.sendgrid.Mail;
import com.sendgrid.Method;
import com.sendgrid.Request;
import com.sendgrid.SendGrid;

Email from = new Email("<FROM_EMAIL>");
String subject = "<SUBJECCT>";
Email to = new Email("<TO_EMAIL>");
Content content = new Content("text/plain", message);
Mail mail = new Mail(from, subject, to, content);
SendGrid sg = new SendGrid(SendGridKey);
Request request = new Request();
try {
    request.setMethod(Method.POST);
    request.setEndpoint("mail/send");
    request.setBody(mail.build());
    sg.api(request);
    log.info("Main sent successfully");
} catch (IOException ex) {
    log.info("Error while sending mail: {}", ex.toString());
}