逃避空白有问题吗？系统找不到路径。

Question

以下代码：

import os
dirPath = 'f:/x/finance-2020/AI/coursera-CNN/work/week4/Face\ Recognition/weights'
print(dirPath)
X = os.listdir(dirPath)
print(X)

失败情况如下：

Traceback (most recent call last):
  File "test.py", line 6, in <module>
    X = os.listdir(dirPath)
FileNotFoundError: [WinError 3] The system cannot find the path specified: 'f:/x/finance-2020/AI/courser
a-CNN/work/week4/Face\\ Recognition/weights'

但是，当在另一个目录中运行时，它可以工作：

import os
dirPath = 'f:/x/finance-2020/AI/coursera-CNN/work/week4'
print(dirPath)
X = os.listdir(dirPath)
print(X)

$ python test.py
f:/x/finance-2020/AI/coursera-CNN/work/week4
['Face Recognition', 'Neural Style Transfer', 'test.py']

我怀疑逃避空白角色是个错误，但我不知道为什么会这样。

Answer 1

你可以使用普通字符串而不用转义空格-

dirPath = 'f:/x/finance-2020/AI/coursera-CNN/work/week4/Face Recognition/weights'

但是，您可以考虑使用os.path操作来构建健壮的路径-

dirPath = os.path.join('f:', os.sep, 'x', 'finance-2020', 'AI', 'coursera-CNN', 
'work', 'week4', 'Face Recognition', 'weights')

或者，更确切地说，像@Tomerikoo所建议的那样，使用pathlib.Path -

from pathlib import Path
dirPath = Path('f:/x/finance-2020/AI/coursera-CNN/work/week4/Face Recognition/weights')