如何用Python加密数据？

Question

如何使用Python加密数据？

就像数据是Hello, I am a coder!一样

如果密码是123AAVVC

然后如何将Hello, I am a coder加密为不可读字符(如0000 0000 0101 0101 )

并且只有在密码为"123AAVVC"的情况下才被解密到"123AAVVC"。

这是我的密码：

def InputPassword():
    Msg = "Enter your password: "
    InputPassword = input(Msg)
    return InputPassword

def InputData():
    Msg = "Enter your data: "
    InputData = input(Msg)
    return InputData


def Encode():
    Psd = InputPassword()
    Data = InputData()
    LenPsd = len(Psd)
    if LenPsd >= 8: #This will allow user to enter password that has 8 or more character
        if Psd:
            pass
            #Rest of the code, I know till here.
        else:
            print("Error!")
    else:
        print("Passord is too short!")

if __name__ == '__main__':
    try:
        Encode()
    except:
        pass

请帮助我编写这个prgram，我是Python编程新手。

提前谢谢。

Answer 1

听起来你想要加密，因为你使用的是密码。

您可以使用一些简单的方法，如pycryptodome，来制作不可破解的密码：

def __EncryptionBase(text, password):
    iv = get_random_bytes(16)
    cipher = AES.new(password, AES.MODE_CBC, iv=IV)
    padded_data = pad(text.encode(), cipher.block_size)
    ciphertext = cipher.encrypt(padded_data)
    return IV + ciphertext

def __DecryptionBase(text, password, IV):
    cipher = AES.new(password, AES.MODE_CBC, iv=IV)
    paddedBytes = cipher.decrypt(text)
    originalBytes = unpad(paddedBytes, cipher.block_size)
    return originalBytes

如果您需要进一步简化上述代码，请发表评论

根据要求，一个没有任何包和很少代码行的密码。这几乎是最简单的加密，给你；

state = [None] * 256
p = q = None


def setKey(key):
    global p, q, state
    key = [ord(c) for c in key]
    state = [n for n in range(256)]
    p = q = j = 0
    for i in range(256):
        if len(key) > 0:
            j = (j + state[i] + key[i % len(key)]) % 256
        else:
            j = (j + state[i]) % 256
        state[i], state[j] = state[j], state[i]


def byteGenerator():
    global p, q, state
    p = (p + 1) % 256
    q = (q + state[p]) % 256
    state[p], state[q] = state[q], state[p]
    return state[(state[p] + state[q]) % 256]


def encrypt(inputString, password):
    setKey(password)

    a = [ord(p) ^ byteGenerator() for p in inputString]
    b = ""
    for i in a:
        b += str(i) + ","
    b = b[:-1]
    return b


def decrypt(YourCipheredNumericList, password):
    setKey(password)
    a = YourCipheredNumericList.split(",")
    if a[-1] == "":
        a.pop()
    b = []
    for i in a:
        b.append(int(i))
    return "".join([chr(c ^ byteGenerator()) for c in b])

a = encrypt("hello world", "123")
print(a)
b = decrypt(a, "123")
print(b)

这是对你的挑战。使用上面简单的加密，我给您创建了两条隐藏的消息，试图破解它们，并告诉我我的秘密:D

容易打破(我不到2分钟)：

MyFirstSecretMessage = decrypt("66,28,211,12,44,178,181,41,254,43,244,148,110,52,56,175", *MySecretPassword*)

很难(我个人不能破坏这条信息)

MySecondSecretMessage = decrypt("129,189,215,167,37,158,208,75,4,161,96,213", *MySecretPassword*)