不与APEX代码合并

Question

我将机会id发送到mySourceId到例程中，并运行应该是标准的Docusign例程。我们有一个按钮来完成这个合并使用标准的DocuS传例程，但正在试图绕过所有额外的按钮点击，用户必须忍受。

我有一个模板，该模板可以在文档上创建，并可在文档上使用与Salesforce相关的自定义字段标记。文件里有我遗漏的东西吗？

        //create the emptyenvelope connecting it to the SF object
        myEnvelope = dfsle.EnvelopeService.getEmptyEnvelope(new dfsle.Entity(**mySourceId**));

        //use the Recipient.fromSource method to create the Recipient
        dfsle.Recipient myRecipient = dfsle.Recipient.fromSource(sender.name, // Recipient name
                                                                 sender.eAddress, // Recipient email
                                                                 null, //Optional phone number
                                                                 sender.role, //Role Name. Specify the exact role name from template
                                                                 new dfsle.Entity(**mySourceId**)); //source object for the Recipient
        //add email detail for the envelope
        myEnvelope = myEnvelope.withEmail(settingsDocusignTemplate.get(sourceName).email_subject__c, settingsDocusignTemplate.get(sourceName).email_body__c);

        //Could provide automatic notifications as well based off of criteria
        final boolean dfsle_reminder = settingsDocusignTemplate.get(sourceName).reminder__c;
        final integer dfsle_remindAfterDays = Integer.valueOf(settingsDocusignTemplate.get(sourceName).remindAfterDays__c); //wait before sending reminder
        
        //add Recipient to the Envelope
        myEnvelope = myEnvelope.withRecipients(new List<dfsle.Recipient> { myRecipient });

        //create a new document for the Envelope
        dfsle.Document myDocument =     dfsle.Document.fromTemplate((dfsle.UUID)templateInfo.get('UUID'), // templateId in dfsle.UUID format
        (String)templateInfo.get('name')); // name of the template

        //add document to the Envelope
        myEnvelope = myEnvelope.withDocuments(new List<dfsle.Document> { myDocument });

    try {
            
        System.debug('\tSending Envelope');
        dfsle.EnvelopeService.sendEnvelope(myEnvelope, // The envelope to send
                                                    true); // Send now?
    } catch (dfsle.DocuSignException docusignExcpt) {
        ErrorLogUtil.createErrorLogData(docusignExcpt,CLASS_NAME,METHOD_NAME,null,null);
    } catch (Exception excp) {
        ErrorLogUtil.createErrorLogData(excp,CLASS_NAME,METHOD_NAME,null,null);
    }

Answer 1

尝试在“为信封创建一个新文档”之后将其添加到您的代码中。

String opptyStr = (String) myOpportunity.Id + '~Opportunity';
        dfsle.CustomField myField = new dfsle.CustomField ('text', 'DSFSSourceObjectId', opptyStr, null, false, false);

//add document to the Envelope
myEnvelope = myEnvelope.withDocuments(new List<dfsle.Document> { myDocument })
.withCustomFields(new List<dfsle.CustomField> {myField});

从技术上讲，合并字段是不支持的，但是我们可以通过使用此代码的自定义字段来解决这个问题。

Answer 2

withCustomFields(新List {myField})

如何将多个字段添加到新的List {myField}列表中？

Answer 3

最后看起来是这样的；

        templateInfo.put('Source_Reference',(String) mySourceId + '~Opportunity');

        dfsle.CustomField sourceField = new dfsle.CustomField ('text', 'DSFSSourceObjectId', (String)templateInfo.get('Source_Reference'), null, false, false);

        //add document to the Envelope
        myEnvelope = myEnvelope.withDocuments(new List<dfsle.Document> { myDocument });

        //populate the custom fields on the Envelope
        myEnvelope = myEnvelope.withCustomFields(new List<dfsle.CustomField> {sourceField});