如果没有shell脚本中的"awk“，我如何做到这一点？

Question

我想读一个有一些条件的文本文件。

111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 123"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /favicon.ico HTTP/1.1" 404 - "
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 206"
111.196.10.3 - - [20/Jan/2020:19:43:50 +0200] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 377"
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /sit-3-shine.7.gif HTTP/1.1" 404 - "
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 375"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET /sit3-shine.7.gif HTTP/1.1" 200 15811"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 375"
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET /sit3-shine.7.gif HTTP/1.1" 200 15811"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 299"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /sit3-shine.7.gif HTTP/1.1" 200 15811"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 299"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET /sit3-shine.7.gif HTTP/1.1" 200 15811"
111.196.10.2 - - [20/Jan/2020:07:00:50 +0100] "GET /favicon.ico HTTP/1.1" 404 -"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "HEAD / HTTP/1.1" 304 299"
111.196.10.3 - - [20/Jan/2020:07:00:50 +0100] "GET / HTTP/1.1" 200 302"
111.196.10.1 - - [20/Jan/2020:07:00:50 +0100] "GET /thttpd_powered_2.gif HTTP/1.1" 200 2114"

1:我想要一个脚本来计算文本文件中的IP地址，并给我这样的输出

111.196.10.1  8
111.196.10.2  8
111.196.10.3  7

为此，我写了一个脚本。

cat file | awk '{print $1}' | sort | uniq -c | sort -nr | awk '{print $2" "$1}'

它正常工作，但我希望它没有"awk“

2 :我的第二个要求是，只有当第二个行的最后一个数以2开头时，才算IP地址。

111.196.10.1  7
111.196.10.3  7
111.196.10.2  5

为此，我写了一个剧本

grep '^[^"]*"[^"]*" 2' file | cut -d' ' -f1 | sort | uniq -c | sort -nr | awk '{print $2" "$1}'

它也能正常工作，但我希望它没有"awk“

Answer 1

1. 您只能获得第一列的剪切，然后排序产生的IP，并计算它们的Uniq。

剪切-f1 -d‘’文件排序-n \ uniq -c

如果第二个到最后一个数字以一个开始，那么只需要添加一个Grep就行了。

grep -E '20-9* 0-9+"$‘t\x\x -f1 -d’‘\x{e76f}\x{e76f}{##*$$}{##*$$}

在样本输入上测试。

Answer 2

没有awk。

grep -oE '([0-9]+\.){3}[0-9]+' Input_file | sort | uniq -c

用awk

请您试一试，在一个awk中完成它。

awk '
match($1,/([0-9]+\.){3}[0-9]+/){
  arr[substr($0,RSTART,RLENGTH)]++
}
END{
  for(key in arr){
    print key,arr[key]
  }
}
' Input_file

或者，如果第一个字段仅为ip地址，则无需在数组索引中提到substr，我们可以直接使用$1，如下所示。

awk '
match($1,/([0-9]+\.){3}[0-9]+/){
  arr[$1]++
}
END{
  for(key in arr){
    print key,arr[key]
  }
}
'  Input_file

解释：添加了上面的详细说明。

awk '                                 ##Starting awk program from here.
match($1,/([0-9]+\.){3}[0-9]+/){      ##using match function to match IP address regex in current line.
  arr[substr($0,RSTART,RLENGTH)]++    ##Create array arr which has index as sub string of matched regex from RSTART to RLENGTH.
}
END{                                  ##Starting END block of this program from here.
  for(key in arr){                    ##Traversing through arr from here.
    print key,arr[key]                ##printing key and array value here.
  }
}
' Input_file                          ##Mentioning Input_file name here.

Answer 3

您可以使用read从输入读取两个字段，然后以不同的顺序回显它们。

所以替换

awk '{print $2" "$1}'

使用

while read count ip; do
    echo "$ip $count"
done