尝试创建一个带有文本库的连接4游戏，然后在以后实现GUI。

Question

class Board:    
    def __init__(self, N):
        '''Board for a Connect-N game, the board will have N+2 Col and N+3 Rows'''
        self.num_row = N + 3
        self.num_col = N + 2        
        self.cols = [Column(self.num_row) for i in range(self.num_col)]
        self.row = [Column(self.num_col) for i in range(self.num_row)]
        pass
        #return
    
    def display(self):
        '''display the board'''
        
        
        
        print ('\u26AA' '\u26AB')         
        #for rown in range(3):
        #    for col in range(2):
        #        btn = tk.Button(width = '5',height = '2', text = '')
        #        btn.bind("<Button-1>", on_btn_click)
        #        btn.grid(row = rown, column = col )
    
    def drop_disk(self, c):
        '''drop a disk at column c'''
        pass

    def check_winning_condition(self):
        '''check if there is a winner'''
        return True
    
class Column:
    def __init__(self, r):
        '''each column has r rows'''
        self.rows = [0]*r
    
N = 4 #standard Connect-4
board = Board(N)
board.display()

我正在尝试创建一个连接-4游戏，但不确定如何做。我得到了一些大纲，但不知道如何创建它。我正在尝试创建一个2列3行的板。这张照片是我想要的样子，但没有用。

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Answer 1

您可以使用__str__方法打印您的板：

一旦游戏按照您需要的方式工作，您可以轻松地在一个单独的文件集中构建一个带有tkinter的图形用户界面。

在下面的示例中，我使用list of lists来表示董事会。我更改了设置，以表示传统的连接-4的6行和7列。

class Board:    
    def __init__(self, N):
        '''Board for a Connect-N game, the board will have N+2 Col and N+3 Rows'''
        self.num_row = N + 2
        self.num_col = N + 3        
        self.cells = [[None for _ in range(self.num_col)] for _ in range(self.num_row)]
    
    def __str__(self):
        res = []
        for row in self.cells:
            for cell in row:
                c = cell
                if cell is None:
                    c = '.'
                res.append(f'{c} ')
            res.append('\n')
        return ''.join(res)

    
    def drop_disk(self, c, player='X'):
        '''drop a disk at column c
        return True if successful
        '''
        for r, row in enumerate(self.cells):
            if row[c] is None:
                continue
            elif r == 0:
                break
            self.cells[r-1][c] = player
            return True
        else:   # this executes when there is `no break`
            self.cells[r][c] = player
            return True
        return False
        

    def check_winning_condition(self):
        '''check if there is a winner'''
        return True

N = 4 #standard Connect-4
board = Board(N)
print(board)

输出：

. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 

为了测试输出，我还添加了drop_disk方法；如果成功播放了磁盘，则返回True，否则返回False。

print(board.drop_disk(3, 'X'))
print(board)
print(board.drop_disk(3, 'O'))
print(board)
print(board.drop_disk(4, 'X'))
print(board)
print(board.drop_disk(5, 'O'))
print(board)
print(board.drop_disk(3, 'X'))
print(board)
print(board.drop_disk(3, 'O'))
print(board)
print(board.drop_disk(3, 'X'))
print(board)
print(board.drop_disk(3, 'O'))
print(board)
print(board.drop_disk(3, 'X'))
print(board)
print(board.drop_disk(3, 'O'))
print(board)

输出：

True
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . X . . . 

True
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . O . . . 
. . . X . . . 

True
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . O . . . 
. . . X X . . 

True
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . O . . . 
. . . X X O . 

True
. . . . . . . 
. . . . . . . 
. . . . . . . 
. . . X . . . 
. . . O . . . 
. . . X X O . 

True
. . . . . . . 
. . . . . . . 
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X X O . 

True
. . . . . . . 
. . . X . . . 
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X X O . 

True
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X X O . 

False
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X X O . 

False
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X . . . 
. . . O . . . 
. . . X X O .