XSLT3.0将转换后的节点提取为多个文档

Question

我有这个XML结构

<doc>
  <Bundle>
    <entry>
      <Observation>
          <id value="o1-3" />
          <subject>
            <reference value="Subject/1" />
          </subject>
          <valueQuantity>
            <value value="400" />
            <unit value="U" />
          </valueQuantity>
          <referenceRange>
            <low>
              <value value="0" />
              <unit value="U" />
            </low>
            <high>
              <value value="45" />
              <unit value="U" />
            </high>
          </referenceRange>
        </Observation>
    </entry>
    <entry>
        <Observation>
          <id value="o8-3" />
          <subject>
            <reference value="Subject/1" />
          </subject>
          <valueQuantity>
            <value value="0.39" />
            <unit value="L" />
          </valueQuantity>
          <referenceRange>
            <low>
              <value value="0.14" />
              <unit value="L" />
            </low>
            <high>
              <value value="0.35" />
              <unit value="L" />
            </high>
          </referenceRange>
        </Observation>
    </entry>
  </Bundle>
  <Bundle>
    <entry>
        <Observation>
          <id value="o3-4" />
          <subject>
            <reference value="Subject/2" />
          </subject>
          <valueQuantity>
            <value value="10" />
            <unit value="U" />
          </valueQuantity>
          <referenceRange>
            <low>
              <value value="3" />
              <unit value="U" />
            </low>
            <high>
              <value value="30" />
              <unit value="U" />
            </high>
          </referenceRange>
        </Observation>
    </entry>
    <entry>
       <Observation>
          <id value="o15-4" />
          <subject>
            <reference value="Subject/2" />
          </subject>
          <valueQuantity>
            <value value="7.1" />
            <unit value="m" />
          </valueQuantity>
          <referenceRange>
            <low>
              <value value="3.5" />
              <unit value="m" />
            </low>
            <high>
              <value value="5.0" />
              <unit value="m" />
            </high>
          </referenceRange>
        </Observation>
    </entry>
  </Bundle>
</doc>

我现正发展以下机制：

如果entry

• Extract

1. 解释valueQuantity是否偏离referenceRange，则将按Observation/subject分组的Observation节点转换为单独的文档。

正确解释的Observation和提取的文档如下：

<?xml version="1.0" encoding="UTF-8"?>
<Interpretation xmlns="http://intelli.org/interpretation">
  <Subject>Subject/1</Subject>
  <Observations>
    <id value="o1-3"/>
    <subject>
      <reference value="Subject/1"/>
    </subject>
    <valueQuantity>
      <value value="400"/>
      <unit value="U"/>
    </valueQuantity>
    <referenceRange>
      <low>
        <value value="0"/>
        <unit value="U"/>
      </low>
      <high>
        <value value="45"/>
        <unit value="U"/>
      </high>
  </referenceRange></Observations></Interpretation>

我的XSLT：

<!-- Interpretation Starts -->
<xsl:template match="valueQuantity">
  <xsl:param name="value" as="xs:double*" select="value/@value" />
  <xsl:param name="low" as="xs:double*" select="following::referenceRange[1]/low/value/@value" />
  <xsl:param name="high" as="xs:double*" select="following::referenceRange[1]/high/value/@value" />
  <xsl:if test="$value lt $low or $value gt $high">
    <xsl:element name="Interpretation">
    </xsl:element>
  </xsl:if>
  <!-- Interpretation Ends -->
  <!-- Identity Transform -->
  <xsl:copy-of select="." />
  <!-- Extraction Starts: Locality? -->
  <xsl:for-each select="parent::Observation">
     <xsl:result-document include-content-type="no" href="/interpret&amp;extract/deviation/{concat('interpretation/', id/@value, '.xml')}">
      <xsl:copy-of select="." />
    </xsl:result-document>
  </xsl:for-each>
</xsl:template>

Answer 1

我想(因为您还没有清楚地解释)，您正在尝试将具有相同entry/subject/reference值的所有entry/subject/reference元素写入相同的输出文件。规范不允许这样做(原因有很多:结果将取决于执行顺序，并行执行将变得非常困难，产生的XML文档将没有外部包装器元素)。

相反，对输入进行单独的传递，以生成此输出文件，使用以下内容

<xsl:for-each-group select="entry" group-by="subject/reference/@value">
   <xsl:result-document href="{...}">
      <wrapper>
         <xsl:copy-of select="current-group()"/>
      </wrapper>
   </xsl:result-document>
</xsl:for-each-group>