按值排序字典[Key：[Key: Value]] - Swift

Question

我有一个分词，看起来是这样的：

var dict = [Int: [String: Any]]()

dict[1] = ["nausea": 23, "other": "hhh"]
dict[2] = ["nausea": 3, "other": "kkk"]
dict[3] = ["nausea": 33,  "other" : "yyy"]

我想根据字典值对字典进行排序，因为关键字“恶心”从最少到最大。

像这样：

sortedDict = [2: ["nausea": 3, "other": "kkk"], 1: ["nausea": 23, "other": "hhh"], 3: ["nausea": 33,  "other" : "yyy"]]

我尝试使用.sort()来玩它：

let sortedDict = dict.sort( { ($0["nausea"] as! Int) > ($1["nausea"] as! Int) })

但是，很明显，它没有起作用，因为“恶心”并不是二叉神经的关键

有人能告诉我他们会怎么做吗？提前感谢！

Answer 1

Dictionary是按设计无序的，正如文档明确指出的那样：

每个字典都是键值对的无序集合.

您可能正在寻找像Array这样的有序类型。

var arrayDict = [
    ["nausea": 23, "other": "hhh"],
    ["nausea": 3, "other": "kkk"],
    ["nausea": 33,  "other" : "yyy"]
]

let sorted = arrayDict.sorted { $0["nausea"] as! Int < $1["nausea"] as! Int }
print(sorted)

Update：更好的是，正如@LeoDabus在注释中建议的那样，您可以使用自定义对象数组：

struct MyObject {
    var nausea: Int
    var other: String
}
var array = [
    MyObject(nausea: 23, other: "hhh"),
    MyObject(nausea: 3, other: "kkk"),
    MyObject(nausea: 33, other: "yyy")
]

let sorted = array.sorted { $0.nausea < $1.nausea }
print(sorted)