通过arg解析,我可以同时解析已知的和未知的args。
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('--foo')
known, unknown = parser.parse_known_args(['--foo', 'BAR', 'spam'])
print(known)
# Namespace(foo='BAR')
print(unknown)
# ['spam']你怎么能用typer做这件事?
发布于 2020-11-09 18:46:38
运行此命令:
from sys import argv
import typer
app = typer.Typer()
@app.command(
context_settings={"allow_extra_args": True, "ignore_unknown_options": True}
)
def main(foo: str = typer.Option(...), unknown_args: typer.Context = typer.Option(None)):
typer.echo(f"known arg: {foo}")
for unknown_arg in unknown_args.args:
typer.echo(f"Got extra arg: {unknown_arg}")
if __name__ == "__main__":
argv.extend(["--foo", "BAR", "spam"])
app()将产出:
known arg: BAR
Got extra arg: spam来源:
https://stackoverflow.com/questions/64757552
复制相似问题