我在Xamarin.Forms,中创建了一个控件,允许我显示带有ContentView和Lottie动画的可重用错误视图。
我的视图包含:Lottie动画,2 Labels (标题和描述)和“重试”Button。
Lotie动画设置如下,因为我希望动画只显示一次:
<lottie:AnimationView
x:Name="networkErrorAnimationView"
Animation="resource://lottie_error_no_network.json?assembly=ShellAppSample"
AnimationSource="EmbeddedResource"
BackgroundColor="Transparent"
AutoPlay="True"
HeightRequest="200" WidthRequest="200"
VerticalOptions="Center" HorizontalOptions="Center"
Clicked="NetworkErrorAnimationView_Clicked"/>问题是,当我从父视图显示错误控制时,动画已经播放:
<ctrl:ErrorView IsVisible="{Binding ShowErrorView, Converter={StaticResource BoolToVisibilityConverter}}"
Title="{Binding ErrorTitle}"
Description="{Binding ErrorDescription}"
ErrorKind="{Binding ErrorKind}"
RetryButtonCommand="{Binding RetryCommand}" />我想知道是否有一种方法将一个事件绑定到控件的IsVisible属性,此时重新启动相应的动画?
发布于 2020-11-10 03:11:01
您可以为ctrl:ErrorView添加一个属性,然后在开始时将AutoPlay设置为false。
这是ctrl:ErrorView的布局。
<ContentView xmlns="http://xamarin.com/schemas/2014/forms"
xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
xmlns:forms="clr-namespace:Lottie.Forms;assembly=Lottie.Forms"
x:Name="MyErrorView"
x:Class="App13.ErrorView">
<ContentView.Content>
<StackLayout>
<forms:AnimationView
x:Name="animationView"
Animation="1.json"
AnimationSource="AssetOrBundle"
RepeatCount="1"
AutoPlay="False"
WidthRequest="100"
HeightRequest="100"/>
<Label x:Name="title" Text="test" />
<Label Text="Hello Xamarin.Forms!" />
</StackLayout>
</ContentView.Content>
</ContentView>这是ctrl:ErrorView的背景代码。然后我添加IsStartAnimationView属性。如果IsStartAnimationView的绑定值为true。然后播放动画。
public partial class ErrorView : ContentView
{
public string TitleText
{
get { return (string)GetValue(TitleTextProperty); }
set { SetValue(TitleTextProperty, value); }
}
public static readonly BindableProperty TitleTextProperty = BindableProperty.Create(
propertyName: "TitleText",
returnType: typeof(string),
declaringType: typeof(ErrorView),
defaultValue: "",
defaultBindingMode: BindingMode.TwoWay,
propertyChanged: TitleTextPropertyChanged);
private static void TitleTextPropertyChanged(BindableObject bindable, object oldValue, object newValue)
{
// var control = (ErrorView)bindable;
// control.title.Text = newValue.ToString();
}
public bool IsStartAnimationView
{
get { return (bool)GetValue(IsStartAnimationViewProperty); }
set { SetValue(IsStartAnimationViewProperty, value); }
}
public static readonly BindableProperty IsStartAnimationViewProperty = BindableProperty.Create(
propertyName: "IsStartAnimationView",
returnType: typeof(bool),
declaringType: typeof(ErrorView),
defaultValue: false,
defaultBindingMode: BindingMode.TwoWay,
propertyChanged: IsStartAnimationViewChanged);
private static void IsStartAnimationViewChanged(BindableObject bindable, object oldValue, object newValue)
{
// throw new NotImplementedException();
var MyValue =(bool) newValue;
if (MyValue == true) {
var control = (ErrorView)bindable;
control.animationView.PlayAnimation();
}
}
public ErrorView()
{
InitializeComponent();
this.Content.BindingContext = this;
}
}
}在Contentpage中使用此控件。
<ctrl:ErrorView IsVisible="{Binding Isfavourite}" TitleText="{Binding Name}" IsStartAnimationView="{Binding IsStart}" ></ctrl:ErrorView>我使用按钮单击事件来进行测试。
private async void Button_Clicked(object sender, System.EventArgs e)
{
myViewModel.IsStart = !myViewModel.IsStart;
}这是跑龙套。

发布于 2020-11-10 08:40:17
这个解决方案是在另一个论坛上给我的。我只需将此代码添加到控件后面的代码中:
protected override void OnPropertyChanged([CallerMemberName] string propertyName = null)
{
base.OnPropertyChanged(propertyName);
if (propertyName == nameof(IsVisible))
{
if (this.IsVisible)
{
networkErrorAnimationView.PlayAnimation();
}
else
{
networkErrorAnimationView.StopAnimation();
}
}
}https://stackoverflow.com/questions/64755659
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