Ramda数组到多参数函数

Question

给定字符串6-10的输入，我希望获得一个数字[6,6.5,7,7.5,8,8.5,9,9.5,10]的列表。

这就是我想出来的：

const x = "6-10";
const sizeMinMax = R.pipe(R.split('-'), R.map(parseInt))
sizeMinMax(x); //[6,10]

const sizesStepped = (min, max) => R.unfold(minSize => minSize > max ? false : [minSize, minSize + 0.5], min)
sizesStepped(8,10); // [8,8.5,9,9.5,10]

如何将sizeMinMax(x)的输出(它是一个带有2个参数的sizeStepped函数的数组)传输到sizeStepped函数？

Answer 1

用sizesStepped包装R.apply：

​

const sizeMinMax = R.pipe(R.split('-'), R.map(parseInt))

const sizesStepped = (min, max) => R.unfold(minSize => minSize > max ? false : [minSize, minSize + 0.5], min)

const fn = R.pipe(sizeMinMax, R.apply(sizesStepped));

const x = "6-10"

const result = fn(x)

console.log(result); // [8,8.5,9,9.5,10]

<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>

​

Answer 2

您可以通过实现range方法在vanilla JavaScript中这样做。

​

const range = (start, stop, step) =>
  Array.from({ length: (stop - start) / step + 1 }, (_, i) => start + i * step);

const x = '6-10';
const [s, e] = x.split('-');
const step = 0.5;
const ret = range(+s, +e, step);
console.log(ret);

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