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如何将以下JSON字符串转换为字典C#
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Stack Overflow用户
提问于 2020-11-22 02:25:51
回答 2查看 138关注 0票数 0

我正在尝试将以下JSON响应字符串转换为C# Dictionary

代码语言:javascript
复制
{
  {
  "type": "Select",
  "name": "timezone",
  "label": "Timezone",
  "description": "Select the city closest to you that shares your same timezone.",
  "multiOptions": {
    "US/Pacific": "(UTC-8) Pacific Time (US & Canada)",
    "US/Mountain": "(UTC-7) Mountain Time (US & Canada)",
    "US/Central": "(UTC-6) Central Time (US & Canada)",
    "US/Eastern": "(UTC-5) Eastern Time (US & Canada)",
    "America/Halifax": "(UTC-4)  Atlantic Time (Canada)",
    "America/Anchorage": "(UTC-9)  Alaska (US & Canada)",
    "Pacific/Honolulu": "(UTC-10) Hawaii (US)",
    "Pacific/Samoa": "(UTC-11) Midway Island, Samoa",
    "Etc/GMT-12": "(UTC-12) Eniwetok, Kwajalein",
    "Canada/Newfoundland": "(UTC-3:30) Canada/Newfoundland",
    "America/Buenos_Aires": "(UTC-3) Brasilia, Buenos Aires, Georgetown",
    "Atlantic/South_Georgia": "(UTC-2) Mid-Atlantic",
    "Atlantic/Azores": "(UTC-1) Azores, Cape Verde Is.",
    "Europe/London": "Greenwich Mean Time (Lisbon, London)",
    "Europe/Berlin": "(UTC+1) Amsterdam, Berlin, Paris, Rome, Madrid",
    "Europe/Athens": "(UTC+2) Athens, Helsinki, Istanbul, Cairo, E. Europe",
    "Europe/Moscow": "(UTC+3) Baghdad, Kuwait, Nairobi, Moscow",
    "Iran": "(UTC+3:30) Tehran",
    "Asia/Dubai": "(UTC+4) Abu Dhabi, Kazan, Muscat",
    "Asia/Kabul": "(UTC+4:30) Kabul",
    "Asia/Yekaterinburg": "(UTC+5) Islamabad, Karachi, Tashkent",
    "Asia/Calcutta": "(UTC+5:30) Bombay, Calcutta, New Delhi",
    "Asia/Katmandu": "(UTC+5:45) Nepal",
    "Asia/Omsk": "(UTC+6) Almaty, Dhaka",
    "India/Cocos": "(UTC+6:30) Cocos Islands, Yangon",
    "Asia/Krasnoyarsk": "(UTC+7) Bangkok, Jakarta, Hanoi",
    "Asia/Hong_Kong": "(UTC+8) Beijing, Hong Kong, Singapore, Taipei",
    "Asia/Tokyo": "(UTC+9) Tokyo, Osaka, Sapporto, Seoul, Yakutsk",
    "Australia/Adelaide": "(UTC+9:30) Adelaide, Darwin",
    "Australia/Sydney": "(UTC+10) Brisbane, Melbourne, Sydney, Guam",
    "Asia/Magadan": "(UTC+11) Magadan, Soloman Is., New Caledonia",
    "Pacific/Auckland": "(UTC+12) Fiji, Kamchatka, Marshall Is., Wellington"
  }
}

使用Newtonsoft JSON库,我不知道如何做到这一点。使用在线转换器,它创建一个名为MultiOptions的类,然后将所有这些作为属性。

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回答 2

Stack Overflow用户

回答已采纳

发布于 2020-11-22 11:21:49

是的,有可能,你需要使用System.Reflection

代码语言:javascript
复制
public Root MyDeserializedClass = new Root();
public Dictionary<string, string> MyDictionary = new Dictionary<string, string>();
...
private void Button_Clicked_1(object sender, EventArgs e)
{
   ConvertToDictionaryPair();
}

private void ConvertToDictionaryPair()
{
   PropertyInfo[] properties = MyDeserializedClass.multiOptions.GetType().GetProperties();
   foreach (PropertyInfo property in properties)
   {
       string key = property.Name;
       string value = property.GetValue(MyDeserializedClass.multiOptions).ToString();
       if (!MyDictionary.ContainsKey(key))
           MyDictionary.Add(key, value);
   }
}

模型

代码语言:javascript
复制
public class Root
    {
        public string type { get; set; }
        public string name { get; set; }
        public string label { get; set; }
        public string description { get; set; }
        public MultiOptions multiOptions { get; set; }
    }

    public class MultiOptions
    {
        [JsonProperty("US/Pacific")]
        public string USPacific { get; set; }
        [JsonProperty("US/Mountain")]
        public string USMountain { get; set; }
        [JsonProperty("US/Central")]
        public string USCentral { get; set; }
        [JsonProperty("US/Eastern")]
        public string USEastern { get; set; }
        [JsonProperty("America/Halifax")]
        public string AmericaHalifax { get; set; }
        [JsonProperty("America/Anchorage")]
        public string AmericaAnchorage { get; set; }
        [JsonProperty("Pacific/Honolulu")]
        public string PacificHonolulu { get; set; }
        [JsonProperty("Pacific/Samoa")]
        public string PacificSamoa { get; set; }
        [JsonProperty("Etc/GMT-12")]
        public string EtcGMT12 { get; set; }
        [JsonProperty("Canada/Newfoundland")]
        public string CanadaNewfoundland { get; set; }
        [JsonProperty("America/Buenos_Aires")]
        public string AmericaBuenosAires { get; set; }
        [JsonProperty("Atlantic/South_Georgia")]
        public string AtlanticSouthGeorgia { get; set; }
        [JsonProperty("Atlantic/Azores")]
        public string AtlanticAzores { get; set; }
        [JsonProperty("Europe/London")]
        public string EuropeLondon { get; set; }
        [JsonProperty("Europe/Berlin")]
        public string EuropeBerlin { get; set; }
        [JsonProperty("Europe/Athens")]
        public string EuropeAthens { get; set; }
        [JsonProperty("Europe/Moscow")]
        public string EuropeMoscow { get; set; }
        public string Iran { get; set; }
        [JsonProperty("Asia/Dubai")]
        public string AsiaDubai { get; set; }
        [JsonProperty("Asia/Kabul")]
        public string AsiaKabul { get; set; }
        [JsonProperty("Asia/Yekaterinburg")]
        public string AsiaYekaterinburg { get; set; }
        [JsonProperty("Asia/Calcutta")]
        public string AsiaCalcutta { get; set; }
        [JsonProperty("Asia/Katmandu")]
        public string AsiaKatmandu { get; set; }
        [JsonProperty("Asia/Omsk")]
        public string AsiaOmsk { get; set; }
        [JsonProperty("India/Cocos")]
        public string IndiaCocos { get; set; }
        [JsonProperty("Asia/Krasnoyarsk")]
        public string AsiaKrasnoyarsk { get; set; }
        [JsonProperty("Asia/Hong_Kong")]
        public string AsiaHongKong { get; set; }
        [JsonProperty("Asia/Tokyo")]
        public string AsiaTokyo { get; set; }
        [JsonProperty("Australia/Adelaide")]
        public string AustraliaAdelaide { get; set; }
        [JsonProperty("Australia/Sydney")]
        public string AustraliaSydney { get; set; }
        [JsonProperty("Asia/Magadan")]
        public string AsiaMagadan { get; set; }
        [JsonProperty("Pacific/Auckland")]
        public string PacificAuckland { get; set; }
    }

首先单击Get数据并填充模型,然后单击set Data,然后遍历模型并将每个属性名称和值添加到字典中。

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票数 0
EN

Stack Overflow用户

发布于 2020-11-22 04:53:07

您可以给Newtonsoft一个要反序列化的DTO。

代码语言:javascript
复制
var parsedDto = JsonConvert.DeserializeObject<ParsedJsonResponseDto>(jsonResponse);

其中DTO对象看起来类似于。

代码语言:javascript
复制
public class ParsedJsonResponseDto
{
    [JsonProperty("type")]
    public string Type { get; set; }

    [JsonProperty("name")]
    public string Name { get; set; }

    [JsonProperty("label")]
    public string Label { get; set; }

    [JsonProperty("description")]
    public string Description { get; set; }

    [JsonProperty("multiOptions")]
    public Dictionary<string, string> MultiOptions { get; set; }    
}

既然有了MultiOptions字典中的对象,就可以任意迭代。

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/64950103

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