关于一个自制的猜数游戏的问题

Question

从现在开始的两天，我一直在努力学习python，我正在用这个网站上的python项目来挑战我自己：https://www.upgrad.com/blog/python-projects-ideas-topics-beginners/#1_Mad_Libs_Generator。

我现在在第二场比赛(猜数游戏)。

指示如下：

“”制作一个程序，在这个程序中，计算机随机选择一个介于1到10、1到100之间的数字。然后给用户一个猜测数字的提示。每次用户猜错了，他就会得到另一条线索，他的分数就会降低。线索可以是倍数、可除的、更大的或更小的，也可以是所有的组合。您还需要一些函数来比较输入的数字和猜测的数字，计算两者之间的差异，并检查在这个python项目中是否输入了一个实际的数字。

import random

print("Welcome to the number game. A random number will be generated and you can guess which one it is.")
print("You got three tries.")

number = random.randint(1, 99)
guess = ""  # var to store users guess
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != number and not out_of_guesses:
    if guess_count < guess_limit:
        guess = int(input("Enter a guess: "))
        guess_count += 1
        if guess < number:
            print("Your guess is too small. Try again.")
        elif guess > number:
            print("Your guess is too high. Try again.")
    else:
        out_of_guesses = True

if out_of_guesses:
    print("You are out of guesses. You loose!")
else:
    print("Your guess is correct. You Won!")

输出如下所示：

Welcome to the number game. A random number will be generated and you can guess which one it is.
You got three tries.
Enter a guess: 78
Your guess is too high. Try again.
Enter a guess: 28
Your guess is too small. Try again.
Enter a guess: 29
**Your guess is too small. Try again.**
You are out of guesses. You loose!

我的问题是这条线标记得很强。实际上，在用户输入第三次尝试而没有猜出正确的答案之后，我不想用“您的猜测太.”这一行。将被展示。但是，在用户尝试结束之前，我确实希望显示它。

您对如何调整代码有任何提示吗？

另外，我确实理解了“尝试”和“除了”的概念，但我不知道在哪里添加它才能使游戏在输入错误时更加“流畅”。

亲切的问候

Answer 1

根据当前的代码结构，通过在guess和number比较中添加额外的检查，可以避免在最后一次猜测中打印提示。

关于异常处理，程序的崩溃点涉及用户输入和数字之间的比较。在用户输入的整数转换周围添加异常处理似乎是合适的。在增量guess_count和continue以允许另一个用户输入之前，这样做将允许游戏运行3个有效的输入。

用于引用异常的_变量是一个“一次性”变量--这只是一个常规的名称。然而，在解释的会话中，_将存储先前执行的语句的返回值。

import random

print("Welcome to the number game. A random number will be generated and you can guess which one it is.")
print("You got three tries.")

number = random.randint(1, 99)
guess = ""  # var to store users guess
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != number and not out_of_guesses:
    if guess_count < guess_limit:
        try:
            guess = int(input("Enter a guess: "))
        except ValueError as _:
            print('Wrong input type')
            continue
        guess_count += 1
        if guess < number and guess_count != guess_limit:
            print("Your guess is too small. Try again.")
        elif guess > number and guess_count != guess_limit:
            print("Your guess is too high. Try again.")
    else:
        out_of_guesses = True

if out_of_guesses:
    print("You are out of guesses. You lose!")
else:
    print("Your guess is correct. You Won!")