我的数据如下:
| user | eventorder| postal|
|:---- |:---------:| -----:|
| A | 1 | 60616 |
| A | 2 | 10000 |
| A | 3 | 60616 |
| B | 1 | 20000 |
| B | 2 | 30000 |
| B | 3 | 40000 |
| B | 4 | 30000 |
| B | 5 | 20000 |--我需要解决的问题:在每个事件订购之前,用户需要停多少个不同的站点?
理想的结果如下:
| user | eventorder| postal| travelledStop|
|:---- |:---------:| -----:| ------------:|
| A | 1 | 60616 | 1 |
| A | 2 | 10000 | 2 |
| A | 3 | 60616 | 2 |
| B | 1 | 20000 | 1 |
| B | 2 | 30000 | 2 |
| B | 3 | 40000 | 3 |
| B | 4 | 30000 | 3 |
| B | 5 | 20000 | 3 |以A为例,当事件顺序为1时,它只行驶了60616 - 1站.当事件顺序为2时,它已经行驶了60616站和10000 - 2站.当事件顺序为3时,此用户所走过的不同停止为60616和10000。-2站。
我不允许使用和order分区。我想做这样的事情,如计数(不同(邮政))在(按用户订单按事件顺序分区),但这是不允许的。
有人知道怎么解决这个问题吗?非常感谢!
发布于 2020-12-09 03:42:30
也许最简单的方法是使用子查询并计算“1”:
select t.*,
sum(case when seqnum = 1 then 1 else 0 end) over (partition by usr order by eventorder) as num_postals
from (select t.*,
row_number() over (partition by usr, postal order by eventorder) as seqnum
from t
) t发布于 2020-12-09 02:58:46
我使用了您提供的样本数据(只是A的子集,但这应该是扩展的)。这里的目标实际上是为每一行生成一个数组,该数组累加前一个事件的所有that。
with _temp as (
select 'A' as usr, 1 as EventOrder, '60616' as Postal
UNION ALL
select 'A' as usr, 2 as EventOrder, '10000' as Postal
UNION ALL
select 'A' as usr, 3 as EventOrder, '60616' as Postal
),
_intermediate as (
select usr
, eventorder
, postal
, array_slice(
array_agg(postal)
within group (order by eventorder)
OVER (Partition by usr)
, 0, eventorder) as full_array
from _temp
group by usr, eventorder, postal
)
select usr, eventorder, postal, count(distinct f.value)
from _intermediate i, lateral flatten(input => i.full_array) f
group by usr, eventorder, postal发布于 2020-12-09 03:43:53
我喜欢@Daniel Zagales的回答,但是这里有一个使用dense_rank和sum的方法。
with temp as (
select 'A' as usr, 1 as EventOrder, '60616' as Postal
UNION ALL
select 'A' as usr, 2 as EventOrder, '10000' as Postal
UNION ALL
select 'A' as usr, 3 as EventOrder, '60616' as Postal
UNION ALL
select 'B' as usr, 1 as EventOrder, '20000' as Postal
UNION ALL
select 'B' as usr, 2 as EventOrder, '30000' as Postal
UNION ALL
select 'B' as usr, 3 as EventOrder, '40000' as Postal
UNION ALL
select 'B' as usr, 4 as EventOrder, '30000' as Postal
UNION ALL
select 'B' as usr, 5 as EventOrder, '20000' as Postal
),
temp2 as(
select temp.* ,dense_rank()over(partition by usr,Postal order by EventOrder) rks
from temp
)
select usr,eventorder,postal,sum(case when rks = 1 then 1 else 0 END)over(partition by usr order by EventOrder) travelledStop
from temp2
order by usr,EventOrder 主要是用dense_rank来得到第一次出现,停止而不是总结。
https://stackoverflow.com/questions/65209513
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