Python列表到字符串转换以实现真正的不匹配

Question

输入

rule = ['xor',[{'asset':'pc','operator':'=','basis':true}]] ->

哪个是类型列表？

我想将列表转换为字符串

预期产出(规则)：

类型字符串 -> "(['xor',[{'asset':'pc','operator':'=','basis':true}]])"

我将在eval中进一步使用这一方法，后者需要字符串输入。

rule_out =  (eval(rule, {'true': True}) 

现在rule_out变成

rule_out = ['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]

Answer 1

您可以定义变量来充当“别名”：

# js-like variables
null = None
true = True
false = False

rule1_str = "['xor', [{'asset': 'pc', 'operator': '=', 'basis': true}]]"
rule2_str = "['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]"
rule3_str = "['xor', [{'asset': 'pc', 'operator': '=', 'basis': null}]]"

rule1 = ['xor', [{'asset': 'pc', 'operator': '=', 'basis': true}]]
rule2 = ['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]
rule3 = ['xor', [{'asset': 'pc', 'operator': '=', 'basis': null}]]

for rule in (rule1, rule2, rule3):
    rule_out = eval(str(rule))
    print(rule_out)

for rule in (rule1_str, rule2_str, rule3_str):
    rule_out = eval(rule)
    print(rule_out)

退出：

['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]
['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]
['xor', [{'asset': 'pc', 'operator': '=', 'basis': None}]]
['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]
['xor', [{'asset': 'pc', 'operator': '=', 'basis': True}]]
['xor', [{'asset': 'pc', 'operator': '=', 'basis': None}]]

Answer 2

我认为您可以使用str()函数：

rule = ['xor',[{'asset':'pc','operator':'=','basis':true}]]

rule_str = str(rule)