我有两个SQL表。从另一个表中获取一个引用值,该表存储模块及其ID的列表,但这些描述并不是唯一的。我正在尝试删除表A的副本,但我不知道如何更新表B,使其仅引用单个值。
示例:
Table A: Table B:
-------------------------------- ------------------------------------
ID Description RefID ID Name
-------------------------------- ------------------------------------
1 Test 1 2 1 QuickReports
-------------------------------- ------------------------------------
2 Test 2 1 2 QuickReports
-------------------------------- ------------------------------------我希望结果如下:
Table A: Table B:
-------------------------------- ------------------------------------
ID Description RefID ID Name
-------------------------------- ------------------------------------
1 Test 1 1 1 QuickReports
-------------------------------- ------------------------------------
2 Test 2 1
-------------------------------- 我使用以下代码从表B中删除了副本,但未能更新表A中的记录。每个表都有500多条记录。
WITH cte AS(
SELECT
Name,
ROW_NUMBER() OVER (
PARTITION BY
Name
ORDER BY
Name
)row_num
FROM ReportmodulesTest
)
DELETE FROM cte
WHERE row_num > 1; 发布于 2021-01-08 08:25:26
我找到了一个让这个过程更容易的解决方案。我首先使用Row_Number在表A中查找重复项,并使用SELECT INTO查找临时表。
SELECT
a.Id
, a.Name
, ROW_NUMBER() OVER(PARTITION BY Name ORDER BY Id DESC) RN
INTO
#TestTable
FROM
TableA a WITH(NOLOCK)然后,我将JOIN表A和表B用于查看ID匹配的位置,并确定需要保留的ID以及需要删除的ID:
SELECT
b.Id
, b.Name
, b.RefId
, ToKeep.Id KeepId
, ToDelete.Id DeleteId
FROM
#TestTable ToDelete
JOIN TableB b WITH(NOLOCK)
ON b.RefId = ToDelete.Id
JOIN #TestTable ToKeep
ON ToDelete.Name = ToKeep.Name
AND ToKeep.RN = 1
WHERE ToDelete.RN > 1然后使用类似的语句,我只需更新记录:
UPDATE b
SET
b.RefId = ToKeep.Id,
FROM #TestTable ToDelete
JOIN TableB b WITH(NOLOCK)
ON b.RefId = ToDelete.Id
JOIN #TestTable ToKeep
ON ToDelete.Name = ToKeep.Name
AND ToKeep.RN = 1
WHERE
ToDelete.RN > 1最后,我现在可以删除重复的记录:
DELETE a
FROM #TestTable b
INNER JOIN TableA a
ON b.Id = a.Id
WHERE
b.RN > 1在此之后,您可以使用相同的第一个SELECT语句来确保删除所有重复项。只需删除SELECT INTO语句即可。
感谢我的一位匿名同事提出了这个解决方案,并希望这能帮助到外面的人。
发布于 2020-12-17 12:15:59
在从表B中删除之前,您需要先更新表A。
您将问题标记为MySQL,但该数据库不支持所显示的delete语句。我怀疑您正在运行SQL Server,下面是如何在该数据库中这样做:
update a
set refid = b.minid
from tablea
inner join (select name, id, min(id) over(partition by name) minid from tableb) b
on b.id = a.id and b.minid <> a.id在MySQL中,您可以将相同的查询表述为:
update tablea a
from tablea
inner join (select name, id, min(id) over(partition by name) minid from tableb) b on b.id = a.id
set a.refid = b.minid
where b.minid <> a.id发布于 2020-12-17 12:16:07
您可以使用以下方法更新第一个表:
update a join
(select b.*,
min(id) over (partition by name) as min_id
from b
) b
on a.refid = b.id
set a.refid = b.min_id
where a.refid <> b.min_id;然后,可以使用类似的逻辑删除第二个表中的行:
delete b
from b join
(select b.*,
min(id) over (partition by name) as min_id
from b
) bb
on bb.id = b.id
where b.id <> bb.min_id;https://stackoverflow.com/questions/65340539
复制相似问题