Firebase错误:在process.<anonymous>上使用代码16退出的进程

Question

我一直搞错了，不太清楚到底是怎么回事。

queueFunction
Error: Process exited with code 16
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:275:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at process.exit (internal/process/per_thread.js:167:15)
at Object.sendCrashResponse (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/logger.js:37:9)
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:271:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at processPromiseRejections (internal/process/promises.js:209:33)
at processTicksAndRejections (internal/process/task_queues.js:98:32)

queueMatch
Error: Process exited with code 16
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:275:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at process.exit (internal/process/per_thread.js:167:15)
at Object.sendCrashResponse (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/logger.js:37:9)
at process.<anonymous> (/layers/google.nodejs.functions- 
framework/functions-framework/node_modules/@google-cloud/functions- 
framework/build/src/invoker.js:271:22)
at process.emit (events.js:315:20)
at process.EventEmitter.emit (domain.js:483:12)
at processPromiseRejections (internal/process/promises.js:209:33)
at processTicksAndRejections (internal/process/task_queues.js:98:32) 

这是我创建的函数，它似乎有时执行，然后不执行。

exports.queueFunction = globalFunctions.runWith(runtimeOpts).https.onRequest((request, response) => {

try {
    challengeId = '';
    console.log("Running cron challenge...")
    var timesRun = 0;
    var interval = setInterval(() => {
        timesRun += 1;
        if (timesRun === 12) {
            console.log("Stopping cron challenge interval...")
            clearInterval(interval);
        }
        console.log("Executing challenge match...")
        getChallenges();
    }, 5000);
    response.status(200).send({ success: 'success' });
} catch (error) {
    response.status(500).send({ error: 'error' });
}

});

而队列只是简单地检查集合中是否有匹配队列。

db = admin.firestore();
const tourRef = db.collection('ChallengeQueue');
const snapshot = await tourRef.where('challengeId', '==', challengeId).get();
const queuedata = [];
if (snapshot.empty) {
    console.log('No users online.');
    return;
}
snapshot.forEach(doc => {
    if (doc.id !== playerId) {
        queuedata.push(doc.data());
    }
});

Answer 1

根据给定的错误消息，给定的queueFunction与其无关，因为它是queueMatch函数中的一个错误。

请提供globalFunctions和runtimeOpts对象。目前，我只能假设globalFunctions被定义为import * as globalFunctions from "firebase-functions"。

关于间隔期有时运行的原因，这是因为您正在发出信号，表明函数已准备好在任何间隔回调运行之前被终止(请参见下面)。一旦返回响应，"function“就被认为是安全的关闭--在发送响应后不应该发生任何重要的事件。

您的代码在功能上相当于：

exports.queueFunction = globalFunctions.runWith(runtimeOpts).https.onRequest((request, response) => {

  try {
      challengeId = '';
      console.log("Running cron challenge...")
      var timesRun = 0;
      var interval = 1 /* some number representing the ID of the interval */;
      response.status(200).send({ success: 'success' }); // response sent, terminate function
  } catch (error) {
      response.status(500).send({ error: 'error' }); // response sent, terminate function
  }

});

注意:在上面的代码块中，假设“终止函数”意味着process.exit()被立即调用。实际上，"function“并没有立即终止，但是您的代码应该假定它是。