将字符串转换为多维数组，以在php中计算日期

Question

我有一个字符串，如下所示

Mon[3,9] Tue[3,9] Wed[5,9] Thu[5,11] Fri[5,11] Sat[5,11] Sun[4,10]

我想将这个字符串分解为多维数组，并将Mon、Tue、Wed这样的日子作为键存储，将方括号中的值作为以下每一天的值存储，并以较小的数组形式访问每一天。

Array
(
    [Mon] => [3,9]
    [Tue] => [3,9]
    [Wed] => [5,9]
    [Thu] => [5,11]
    [Fri] => [5,11]
    [Sat] => [5,11]
    [Sun] => [4,10]
)

使用下面的代码，我能够实现它，但是像[3,9] or [5,11]这样的值被视为字符串。

    $atd = $utd = "";
    $dod = "20-12-2020";
    $daysArray = "Mon[3,9] Tue[3,9] Wed[5,9] Thu[5,11] Fri[5,11] Sat[5,11] Sun[4,10]";
    $days = array('Mon','Tue','Wed','Thu','Fri','Sat','Sun');
    preg_match_all("/\[[^\]]*\]/", $daysArray, $matches);
    $dayNum = $matches[0];
    $daysArray = array_combine($days , $dayNum);
    print_r($daysArray);
        
        $valArray = array();
        
        foreach($daysArray as $day=>$val){
            if($day == "Mon" || $day == "Tue"){
              $atd = date("d-m-Y", strtotime("+".$val[0]." days", $dod));
              $utd = date("d-m-Y", strtotime("+".$val[1]." days", $dod));
           }else if($day == "Sun"){
              $atd = date("d-m-Y", strtotime("+".$val[0]." days", $dod));
              $utd = date("d-m-Y", strtotime("+".$val[1]." days", $dod));
           }else if($day == "Wed"){
              $atd = date("d-m-Y", strtotime("+".$val[0]." days", $dod));
              $utd = date("d-m-Y", strtotime("+".$val[1]." days", $dod));
           }else{
              $atd = date("d-m-Y", strtotime("+".$val[0]." 5 days", $dod));
              $utd = date("d-m-Y", strtotime("+".$val[1]." days", $dod));
             }
            }
        } 

当我打印$valArray时，它是一个像下面这样的数组，这是非常糟糕的。

array(
   [0]=>[
   [1]=>4
   [2]=>,
   [3]=>1
   [4]=>0
   [5]=>]
);

请帮帮忙

Answer 1

我想这就是你想要的结果。

$str = 'Mon[3,9] Tue[3,9] Wed[5,9] Thu[5,11] Fri[5,11] Sat[5,11] Sun[4,10]';

$result = [];

$bits = explode(' ', $str); // explode on space between day names
foreach ( $bits as $bit) {
    $b = explode('[', $bit);    // $bit = Mon[3,9] 
    $b[1] = rtrim($b[1], ']');  // $b0 = Mon, B1 = 3,9] so trim off the last ]
    $result[$b[0]] = explode(',', $b[1]); // explode on , to get inner array
}
print_r($result);

结果

Array
(
    [Mon] => Array
        (
            [0] => 3
            [1] => 9
        )
    [Tue] => Array
        (
            [0] => 3
            [1] => 9
        )
    [Wed] => Array
        (
            [0] => 5
            [1] => 9
        )
    [Thu] => Array
        (
            [0] => 5
            [1] => 11
        )
    [Fri] => Array
        (
            [0] => 5
            [1] => 11
        )
    [Sat] => Array
        (
            [0] => 5
            [1] => 11
        )
    [Sun] => Array
        (
            [0] => 4
            [1] => 10
        )
)

Answer 2

试试这个：

$str = 'Mon[3,9] Tue[3,9] Wed[5,9] Thu[5,11] Fri[5,11] Sat[5,11] Sun[4,10]';
// convert main string to array by explode by empty space
$arr = explode(' ', $str);

$newArr = [];

foreach ($arr as $data) {
  // to get all b/n brackets best is to use regEx
  preg_match('#\[(.*?)\]#', $data, $match);
  // for key of new array use all befor 1st bracket
  // and for content explode data b/n brackets by ','
  $newArr[strtok($data, '[')] = explode(',', $match[1]);
}

var_dump($newArr);

结果：

array(7) {  ["Mon"]=> array(2) { [0]=> string(1) "3" [1]=> string(1) "9" } 
            ["Tue"]=> array(2) { [0]=> string(1) "3" [1]=> string(1) "9" }    
            ["Wed"]=> array(2) { [0]=> string(1) "5" [1]=> string(1) "9" } 
            ["Thu"]=> array(2) { [0]=> string(1) "5" [1]=> string(2) "11" } 
            ["Fri"]=> array(2) { [0]=> string(1) "5" [1]=> string(2) "11" } 
            ["Sat"]=> array(2) { [0]=> string(1) "5" [1]=> string(2) "11" } 
            ["Sun"]=> array(2) { [0]=> string(1) "4" [1]=> string(2) "10" } 
    }

Answer 3

以下是一个建议：

$days = "Mon[3,9] Tue[3,9] Wed[5,9] Thu[5,11] Fri[5,11] Sat[5,11] Sun[4,10]";
$individualDays = explode(' ', $days);
$result = [];
foreach ($individualDays as $individualDay) {
    $dates = preg_match_all('/\d+/', $individualDay, $matches);
    $result[substr($individualDay, 0, 3)] = $matches[0];
}

它的工作原理：

• 所有的值都由一个空格隔开，所以我们首先利用它来获得一个可以迭代的单个字符串数组(Mon[3,9]、Tue[3,9]等)。
• 每个字符串的前三个字符是日期指定，我们使用它作为新结果数组的键(使用substr)。
• 我们匹配preg_match_all中的所有数字，并将匹配数组分配给该键。